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Full Discussion: Getting filenames from a directory in single line
Top Forums Shell Programming and Scripting Getting filenames from a directory in single line Post 302459506 by rdcwayx on Monday 4th of October 2010 10:01:03 PM
Old 10-04-2010
Updated from Agama's code, that you need understand the FS (field separator) in awk.
Code:
awk -F \/ '{ printf( "%s ", $NF ) } END { printf( "\n" ); }'

but Chubler_XL's code is more simple.
 

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LEARN ABOUT DEBIAN

py_xls2csv

py_xls2csv(1)						      General Commands Manual						     py_xls2csv(1)

NAME

       py_xls2csv - convert an Excel xls file to a comma separated value csv file

SYNOPSIS

       py_xls2csv  input-file

DESCRIPTION

       This manual page was written for the Debian distribution because the original program does not have a manual page.

       py_xls2csv takes an Excel xls file as an argument and converts it to a comma separated value csv file.  Output is sent to stdout.

       Additional utility scripts can be found in the tools/ directory.

OPTIONS

       This program does not take any command line options.

AUTHOR

       pyexcelerator and py_xls2csv were written by Roman V. Kiseliov <roman@kiseliov.ru>.

       This manual page was written by Kevin Coyner <kcoyner@debian.org> for the Debian system (but may be used by others).  Permission is granted
       to copy, distribute and/or modify this document under the terms of the GNU General Public License, Version 2 any  later	version  published
       by the Free Software Foundation.

       On Debian systems, the complete text of the GNU General Public License can be found in /usr/share/common-licenses/GPL.

SEE-ALSO
       pyexcelerator(1), py_xls2txt(1), py_xls2html(1)

								 October 12, 2006						     py_xls2csv(1)
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