Hello,
I am using a if condition within my awk script and I have a problem with the search pattern.
I would like awk to find all the fields starting with 123. For now I have something like that:
awk '{for(i=1;i<9;i+=2)if($i=="123"...)print $i}' test
but that is not working as... (2 Replies)
Dear Friends,
I have a flat file. To pick certain details we have written an awk where we are facing difficulty.
Sample of flat file.
line 1
line 2
line 3
line 4
line 5
line 6
line 7
line 8
line 9
line 10
line 11
line 12
line 13
line 14 (Matching pattern "Lkm_i-lnr:"can be... (4 Replies)
Hi All,
I have the below file data.txt.Using awk i want to grep all the zone data.Form the below command i can extact data upto of zone i give but i want it should print until next pattern.
awk '/^Total Collection /{c=5;next}c-->0' zin45srs08.tools_utilization
instead of c=5 is it possible... (5 Replies)
Hi All,
I am trying to find numbers with balance greater than 1 and less than equal 2 from the below file using awk
Input file
num ,bal
100199,1.708
100225,0
100226,0
100228,0.771166
100232,2
output file
100199,1.708
100232,2
I am using the following command for this... (2 Replies)
Here Is a problem I am facing with awk.
Query --> I want to search for a string in a file and print next 15 lines below the matched string.
1.We do not have GNU grep so cannot use grep -A or grep -B commands.
2. Instead of passing the search pattern as a string to awk. I want the awk to... (4 Replies)
Hello Guyz
I have been following this forum for a while and the solutions provided are super useful. I currently have a scenario where i need to search for a pattern and start searching by keeping the first pattern as a baseline
ABC
DEF
LMN
EFG
HIJ
LMN
OPQ
In the above text i need to... (8 Replies)
Want to fetch a column with multiple pattern using awk.
How to achieve the same.
Tried
cat test
address : 10.63.20.92/24
address : 10.64.22.93/24
address : 10.53.40.91/24
cat test | awk '{print $3}' |awk -F "/" '{print $1}'
10.63.20.92
10.64.22.93
10.53.40.91
Is there any... (2 Replies)
Want to search a pattern in column
using the below command which not helpful
awk -F"\|" '$1 == '"${VAR}"' {print $1,$2}' file
how to search using "==" with variable other than the below case.
awk -F"\|" '$1 ~ /'"${VAR}"'/ {print $1,$2}' file (14 Replies)
I have this fileA
TEST FILE ABC
this file contains ABC;
TEST FILE DGHT this file contains DGHT;
TEST FILE 123
this file contains ABC,
this file contains DEF,
this file contains XYZ,
this file contains KLM
;
I want to have a fileZ that has only (begin search pattern for will be... (2 Replies)
Hello,
We have wrote shell script for multiple file name search pattern.
file format: <numner>_<20180809>.txt
starting with single number and ending with 8 digits number
Command:
awk -v string="12_1234" -v serch="^+_+$" "BEGIN{ if (string ~/serch$/) print string }"
If sting matches... (4 Replies)
Discussion started by: koti_rama
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)