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Top Forums Shell Programming and Scripting How to get this script work on multiple input files Post 302448771 by Daniel8472 on Friday 27th of August 2010 03:27:54 AM
Old 08-27-2010
Good morning!

I am back in the lab and just used the scipt (needed to midify some parts because some files contain "," instead of ".")

One problem seems to remain so far. While reading a new file the value for "h" is not reset to zero. Thus unless in the following file is a higher value in the $2 the highest $2 value of the previous files is kept and printed.

Code:
BEGIN { h=0 } 
    FNR == 1    { if(header!="") 
                {             
                #printf "%s\n%d\n", header, h;
                print header, h; 
                } 
            header=$0; next; 
            } \
         
    substr($2,3,5)/100000*10^(substr($2,9,3))>h         { h=substr($2,3,5)/100000*10^(substr($2,9,3)) } 

END     { 
    print header, h;
    #printf "%s\n%d\n", header, h;
    }

Output:


Code:
 DWT26R 1 PEP1 CA 10 OH2 SKIPPED: 0 STEP: 1 3,2829
 DWT26R 1 PEP2 CA 10 OH2 SKIPPED: 0 STEP: 1 3,5248
 DWT26R 1 PEP1 CA 11 OH2 SKIPPED: 0 STEP: 1 4,3229
 DWT26R 1 PEP2 CA 11 OH2 SKIPPED: 0 STEP: 1 4,3229
 DWT26R 1 PEP1 CA 12 OH2 SKIPPED: 0 STEP: 1 6,8575
 DWT26R 1 PEP2 CA 12 OH2 SKIPPED: 0 STEP: 1 6,8575
 DWT26R 1 PEP1 CA 13 OH2 SKIPPED: 0 STEP: 1 6,8575
 DWT26R 1 PEP2 CA 13 OH2 SKIPPED: 0 STEP: 1 6,8575
 DWT26R 1 PEP1 CA 14 OH2 SKIPPED: 0 STEP: 1 6,8575
 DWT26R 1 PEP2 CA 14 OH2 SKIPPED: 0 STEP: 1 6,8575

 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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