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Full Discussion: Question on regex with * and .
Top Forums Shell Programming and Scripting Question on regex with * and . Post 302438225 by mirage on Monday 19th of July 2010 06:41:04 AM
Old 07-19-2010
Code:
# echo 3 | grep ^[123456789]+$
# echo 34 | grep ^[123456789]+$
#

but why not the above print "3" and "34" (respectively) if '+' should match one or more of the previous characters?
Last edited by Scott; 07-19-2010 at 07:56 AM.. Reason: Code tags
 

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LEARN ABOUT HPUX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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