Hey
I have an input file containing a list of numbers like:
U01120.CDS.1
D25328.CDS.1
X15573.CDS.1
K03515.CDS.1
L44140.CDS.10
U24183.CDS.1
M97347.CDS.1
U05259.CDS.1
And another input file containing results created on the basis of the above input:
G6PT_HUMAN U01120.CDS.1 -1.9450 3.1706... (1 Reply)
Hi,
I have two files. 1st file has 1 column (huge file containing ~19200000 lines) and 2nd file has 2 columns (small file containing ~6000 lines).
#################################
huge_file.txt
a
a
ab
b
##################################
small_file.txt
a 1.5
b 2.5
ab ... (4 Replies)
I have a file that contains 87 lines, each with a set of coordinates (x & y). This file looks like:
1 200.3 -0.3
2 201.7 -0.32
...
87 200.2 -0.314
I have another file which contains data that was taken at certain of these 87 positions. i.e.:
37 125
42 175
86 142
where the first... (1 Reply)
Hello I am a new unix user, and I have a work related task to compare 2 files and print all of the lines in file 2 that contain a string from file 1 Note: the fields are in different columns in the files. I suspect the is a good use for awk? Thanks for your time & help
File 1
123 232 W343... (6 Replies)
Dear all,
I have a file with two columns - the first column is increasing every 50, the second column is just count (e.g. 5). However, when count is zero, no line is present.
Sample:
1950 7
2000 14
2050 7
2100 13
2150 10
2200 9
2250 7
2300 8
2350 7... (1 Reply)
Dear all,
I have a file with two columns - the first column is increasing every 50, the second column is just count (e.g. 5). However, when count is zero, no line is present.
Sample:
How can I change the file so as to include lines with zero count? e.g. in the previous file to put... (4 Replies)
Hi ,
i will be getting 24 files for one day with a formate like 20131028_01 - 20131028_24 kind of ,i am trying to write a shell script to count the number of files and if the count is not equal to 24 print the missing files names
for A in `seq 0 23`; do ls *20131024_`printf "%02d" $A`*;... (3 Replies)
Hi everyone,
I need to write a script to search a directory, output the name of a file to an ouput file and print the last few lines of the files to the output file such that I would have something like this:
FILE1:
LINE
LINE
LINE
FILE2:
LINE
LINE
LINE
FILE3:
LINE
LINE
LINE... (2 Replies)
Discussion started by: mojoman
2 Replies
LEARN ABOUT PHP
datefmt_set_pattern
DATEFMT_SET_PATTERN(3) 1 DATEFMT_SET_PATTERN(3)IntlDateFormatter::setPattern - Set the pattern used for the IntlDateFormatter
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::setPattern (string $pattern)
DESCRIPTION
Procedural style
bool datefmt_set_pattern (IntlDateFormatter $fmt, string $pattern)
Set the pattern used for the IntlDateFormatter.
PARAMETERS
o $fmt
- The formatter resource.
o $pattern
- New pattern string to use. Possible patterns are documented at http://userguide.icu-project.org/formatparse/datetime.
RETURN VALUES
Returns TRUE on success or FALSE on failure. Bad formatstrings are usually the cause of the failure.
EXAMPLES
Example #1
datefmt_set_pattern(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'First Formatted output with pattern is ' . datefmt_format($fmt, 0);
datefmt_set_pattern($fmt, 'yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'Second Formatted output with pattern is ' . datefmt_format($fmt, 0);
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . $fmt->getPattern();
echo 'First Formatted output is ' . $fmt->format(0);
$fmt->setPattern('yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . $fmt->getPattern();
echo 'Second Formatted output is ' . $fmt->format(0);
?>
The above example will output:
pattern of the formatter is : MM/dd/yyyy
First Formatted output with pattern is 12/31/1969
Now pattern of the formatter is : yyyymmdd hh:mm:ss z
Second Formatted output with pattern is 19690031 04:00:00 PST
SEE ALSO datefmt_get_pattern(3), datefmt_create(3).
PHP Documentation Group DATEFMT_SET_PATTERN(3)