Find the missing file and print

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# 1  
Old 10-28-2013
Find the missing file and print

Hi ,

i will be getting 24 files for one day with a formate like 20131028_01 - 20131028_24 kind of ,i am trying to write a shell script to count the number of files and if the count is not equal to 24 print the missing files names

 for A in `seq 0 23`; do ls *20131024_`printf "%02d" $A`*; done

this gives me a complete list but i just want the missing files any help would be thank full
# 2  
Old 10-28-2013
Instead of ls, use [ (aka test) to check for the existence of the file. If the test fails, then print the name.

# 3  
Old 10-28-2013
can you show me the usage
# 4  
Old 10-28-2013
Read man test or check your shell's manual page (ksh and bash, for example, have a builtin version that they document).

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