help with a script Post: 302425355

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Top Forums UNIX for Dummies Questions & Answers help with a script Post 302425355 by akabir77 on Thursday 27th of May 2010 05:01:23 PM

05-27-2010

Registered User

Quote:

Originally Posted by scottn

Hi.

Using command substitution:

Generally using:

Code:

VAR=$(command)

i.e.

Code:

VAR=$(ps -ef | grep batch_download_x)

Thanks now hwo do I get the time out of the result

I am trying like this

Code:

 VAR=$(ps -ef | grep batch_download_x)
        echo "FTP_FILE_DATE $VAR"

        FTP_HOUR=$(echo $VAR|cut -c5-2)
        FTP_MIN=$(echo $VAR|cut -c5-4)
        FTP_SEC=$(echo $VAR|cut -c5-8)

        echo "Time: $FTP_HOUR:$FTP_MIN:$FTP_SEC"

But I am getting wrong info.

I was reading this thing in internet where it says

Quote:

-c list Cut based on character positions specified by list
(-c 1-72 extracts the first 72 characters of each
line).

but if i say

Code:

FTP_HOUR=$(echo $VAR|cut -c23-2)

it errors out

---------- Post updated at 03:29 PM ---------- Previous update was at 03:27 PM ----------

never mind got it... the last number is not number of character but upto which character...

---------- Post updated at 04:01 PM ---------- Previous update was at 03:29 PM ----------

Question how to get the time that the process was started...

I was using this

Code:

if [ `ps -elf | grep batch_output_x | grep -cv grep` = 0 ]
then
    echo 'Gateway output processing started.' 

else       
	VAR=$(ps -elf | grep batch_output_x )
	echo "FTP_FILE_DATE $VAR"

        FTP_HOUR=$(echo $VAR|cut -c23-24)
        FTP_MIN=$(echo $VAR|cut -c26-27)
        FTP_SEC=$(echo $VAR|cut -c29-30)

        echo "Time: $FTP_HOUR:$FTP_MIN:$FTP_SEC"


fi

but this doesn't work as I get different results depending on how many of that process is running...

akabir77

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