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Top Forums Shell Programming and Scripting Remove spaces in the beginning of a string Post 302425316 by pseudocoder on Thursday 27th of May 2010 03:21:11 PM
Old 05-27-2010
Quote:
Originally Posted by shrutihardas
But what if I want all the spaces removed from a string and the final output that i want is as follows

Code:
norowsselected

how do I achieve this?
Code:
val=$(echo $value |sed 's/ //g' )

should work as well
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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