I need to pass a parameter to a function in a script. My parameter is a string. When I display the parameter within my function, I only get the first word from string I pass in.
How can I make the function receive the whole string (and not terminate at the first space it encounters)?.
part of... (2 Replies)
Hello,
Could anyone help me with some KSH syntax? I'm trying to pass a list as a function parameter in a KSH?
For example I have code like this:
print_counter() {
N=$1
C=$2
for A in $C; do
echo "This is $N number $A"
done
}
NAME=BRICK
COUNT=" 1 2 3 4"
... (2 Replies)
HI all
I have a code like
##############################################
minyear()
{
curryear=$1
echo $curryear
}
##Main Program ##
minyear
exit
#######
when i execute "sh scriptname 2005" output should be like 2005 but the output is blank.
I guess i need to pass parameter to... (3 Replies)
hi,
i have a function say "mask". i'm passing parameters to the function like file_name \$1 |.
inside the function i'm naming the second parameter as position (i.e value of position will be "$1").
i'm passing the position's value like " $position=a"
But it is nor picking the value "$1".... (5 Replies)
Hi guys,
can someome help with this question, I have defined a function that takes a command as a parameter, but when the command is executed from the function it will throw errors because what I believe is a special character escaping issue. I tried using the backslash to escape the pipe | and >... (2 Replies)
hi all,
i have a parameter file of following format, i want a method which can get the value of specific parameter.
parameter file format:
<Parameter Name="FileLocationWindows">
<Description>
The directory location of the logger file.
... (1 Reply)
Hi All,
Just trying to implement the below shell script using AIX ksh shell.
myfunc {
eval "$*"
}
CMD='ls -la /etc/hosts | awk '{print $9"|"$5}''
myfunc $CMD
Keeping getting "|}: not found" errors, any pointers would greatly be appreciated.
Kind Regards
Ed
Please... (2 Replies)
Hi All,
I have created one function for KSH and was running well with one parameter input since I just had to use $1 to get the parameter.
Now I want to do loop for each parameter(actually filenames) . I have try to use do loop, but $i does not resolve to parameter instead it resolves to 1,... (5 Replies)
Discussion started by: mysocks
5 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)