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Top Forums Shell Programming and Scripting Can $? return multiple values? Post 302417417 by jim mcnamara on Thursday 29th of April 2010 01:45:56 PM
Old 04-29-2010
Return values (like $? in shell) from child processes are 8 bit numbers. This is because
the syscall, wait(), truncates a return value from a child process to the lowest 8 bits.

The range for 8 bit numbers is 0->255 (unsigned) or -128 -> 127 (signed).

That is all there is for $? in shell. Nothing else like multiple return values.
 

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WAIT(2) 							System Calls Manual							   WAIT(2)

NAME
wait - wait for process to terminate SYNOPSIS
wait(status) int *status; wait(0) DESCRIPTION
Wait causes its caller to delay until a signal is received or one of its child processes terminates. If any child has died since the last wait, return is immediate; if there are no children, return is immediate with the error bit set (resp. with a value of -1 returned). The normal return yields the process ID of the terminated child. In the case of several children several wait calls are needed to learn of all the deaths. If (int)status is nonzero, the high byte of the word pointed to receives the low byte of the argument of exit when the child terminated. The low byte receives the termination status of the process. See signal(2) for a list of termination statuses (signals); 0 status indi- cates normal termination. A special status (0177) is returned for a stopped process which has not terminated and can be restarted. See ptrace(2). If the 0200 bit of the termination status is set, a core image of the process was produced by the system. If the parent process terminates without waiting on its children, the initialization process (process ID = 1) inherits the children. SEE ALSO
exit(2), fork(2), signal(2) DIAGNOSTICS
Returns -1 if there are no children not previously waited for. ASSEMBLER
(wait = 7.) sys wait (process ID in r0) (status in r1) The high byte of the status is the low byte of r0 in the child at termination. WAIT(2)
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