04-08-2010
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hi all,
I would like to calculate the day of the week using a supplied date.
i.e. 20011012 = Day 5.
Any ideas?
Many thanks,
ligs (4 Replies)
Discussion started by: ligs
4 Replies
2. Programming
Hi ,
I am working at Unix system,using c lang.
I need c fun which return the day of the week .
For example :
0- Sunday.
1- Monday.
....
10x. (4 Replies)
Discussion started by: kamil
4 Replies
3. Shell Programming and Scripting
I need o get yesterday's day of week but im not exactly sure. the actual name is what i want. I can do it with numbers but im not sure with words. (3 Replies)
Discussion started by: rcunn87
3 Replies
4. UNIX for Dummies Questions & Answers
Hi All,
Our system is running on Solaris 8 and we are using US locale. By default the First Day Of Week is Sunday, is it possible for us to change it to Monday?
I have googled it but found very little of use.
THanks in advance. (2 Replies)
Discussion started by: fowlerleftfoot
2 Replies
5. HP-UX
Hi All,
I have date in string format 'YYYY-MM-DD'. I want to know day of the week for this date.
Example. For '2005-08-21' my script should return '0' or Sunday
For '2005-08-22' it should return '1' or Monday
I want piece of code for HP-UX korn shell.
Appreciate reply on this. (5 Replies)
Discussion started by: vpapaiya
5 Replies
6. Shell Programming and Scripting
Hi all, I am trying to get dow from cal using below script
#! /bin/bash
YEAR=`echo $1 | cut -c 1-4`
MONTH=`echo $1 | cut -c 5-6`
DAY=`echo $1 | cut -c 7-8`
for i in 1 2 3 4 5 6 7
do
dayofweek=`cal $MONTH $YEAR | awk '$i == $DAY {printf("%s","$i")}'`
echo $dayofweek... (4 Replies)
Discussion started by: bzylg
4 Replies
7. HP-UX
In HP-UX the date command does not have the "-d" switch like some other *nixes do. I'm working a simple script to tell me, given the day, month and year what day of the week that falls on.
Assuming valid day, month and year input (I'd perform quality checks on the input separately, but not... (5 Replies)
Discussion started by: rwuerth
5 Replies
8. Shell Programming and Scripting
Need assistance . Below code gives me the date but I wanted output as day of the week (wday) .
Code:
use Time::Local;
my $time=timelocal(1,2,3,9,11,2013);
$theTime = localtime($time);
print "$theTime\n";
Result:
Mon Dec 9 03:02:01 2013
Wanted output as only Mon (2 Replies)
Discussion started by: ajayram_arya
2 Replies
9. UNIX for Dummies Questions & Answers
I have been volunteered by my boss to be the sysadmin for our production redhat server. He asked me to tighten the security to avoid mishaps like "rm -f *" that occured not long ago.
Right now, we have 53 users sudo-ing into the machine and it is an audit nightmare. I am wondering if it... (15 Replies)
Discussion started by: alan
15 Replies
10. Shell Programming and Scripting
Hi All,
I have the below requirement ,
if i give the week number for ex 41 i need to get the date for Monday and thursday for this given week. my expected output is 13/10/2014 (Monday's date) and 16/10/2014 (Thursday's date)
I am using GNU LINUX .
Pls help me with your thoughts.
Thanks in... (7 Replies)
Discussion started by: mohanalakshmi
7 Replies
LEARN ABOUT LINUX
setegid
SETEUID(2) Linux Programmer's Manual SETEUID(2)
NAME
seteuid, setegid - set effective user or group ID
SYNOPSIS
#include <sys/types.h>
#include <unistd.h>
int seteuid(uid_t euid);
int setegid(gid_t egid);
Feature Test Macro Requirements for glibc (see feature_test_macros(7)):
seteuid(), setegid():
_BSD_SOURCE || _POSIX_C_SOURCE >= 200112L || _XOPEN_SOURCE >= 600
DESCRIPTION
seteuid() sets the effective user ID of the calling process. Unprivileged user processes may only set the effective user ID to the real
user ID, the effective user ID or the saved set-user-ID.
Precisely the same holds for setegid() with "group" instead of "user".
RETURN VALUE
On success, zero is returned. On error, -1 is returned, and errno is set appropriately.
ERRORS
EPERM The calling process is not privileged (Linux: does not have the CAP_SETUID capability in the case of seteuid(), or the CAP_SETGID
capability in the case of setegid()) and euid (respectively, egid) is not the real user (group) ID, the effective user (group) ID,
or the saved set-user-ID (saved set-group-ID).
CONFORMING TO
4.3BSD, POSIX.1-2001.
NOTES
Setting the effective user (group) ID to the saved set-user-ID (saved set-group-ID) is possible since Linux 1.1.37 (1.1.38). On an arbi-
trary system one should check _POSIX_SAVED_IDS.
Under libc4, libc5 and glibc 2.0 seteuid(euid) is equivalent to setreuid(-1, euid) and hence may change the saved set-user-ID. Under glibc
2.1 and later it is equivalent to setresuid(-1, euid, -1) and hence does not change the saved set-user-ID. Similar remarks hold for sete-
gid().
According to POSIX.1, seteuid() (setegid()) need not permit euid (egid) to be the same value as the current effective user (group) ID, and
some implementations do not permit this.
SEE ALSO
geteuid(2), setresuid(2), setreuid(2), setuid(2), capabilities(7), credentials(7)
COLOPHON
This page is part of release 3.27 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
Linux 2009-10-17 SETEUID(2)