my file looks like this:
101928 101943
101928 101944
101929 101943
101929 101943
101929 102044
i want to insert bc to get answer like this:
101928 101943 000015
101928 101944 000016
101929 101943 000013
101929 101943 000014
101929 102044 000115
total 000173
my... (3 Replies)
Hello people,
awk '{print $0}' input1.txt input2.txt |sort -u
Will give the union of the 2 files. Similarly what is command to get just the diff data (i.e minus) of the 2 files. Can I use the "diff" command to get just the diff data.
Please let me know.
Regards,
Tipsy. (7 Replies)
Hi there,
I have a problem with arithmetic ops in awk.
Here is what my script does right now.
while read nr val ; do
case $nr in
400) awk '$2~/eigenvectors/ {print $NF-'$val'};' input.txt >> output.txt;;
esac
done < frames.txtI have a file named frames.txt with two columns (nr and... (2 Replies)
Hi,
I need to subtract 5 minutes from the date. Example
$date +"%Y-%m-%d-%H.%M.%S" displays 2014-06-26-06.06.38
I want to show it as 2014-06-26-06.01.38 (5 mins are subtracted from date)
Any help would be appreciated. I am currently on AIX version 6.1
-Vrushank (10 Replies)
Hi the below code is failing i am trying to generate do the following:
2014-10-22 11:26:00 (Substract 24 hrs)
should produce
2014-10-21 11:26:00
I need the same formatting below because that gets inputted into code for an... (4 Replies)
I have a specific set (all ending with .bam) of downloaded files in a directory /home/cmccabe/Desktop/NGS/API/2-15-2016. What I am trying to do is use a match to $2 in name to rename the downloaded files. To make things a more involved the date of the folder is unique and in the header of name... (1 Reply)
Hello,
date --date '-60 min ago' +'%Y-%m-%d %H:%M:%S,%3N'
Above command gives the date and time minus 60 minutes
but the problem i am facing is, i do not want to hardcode the value 60
it is stored in a variable var=60
now if i run below command , i get error
date --date '-$var min... (3 Replies)
Hello Folks,
I have a variable output holding date as below -
output = "20141220"
I need to extract a day out of it and store it in another variable i.e. something similar to below -
output1=20141219"
and if the month is changing i.e. date in on 31st or 1st it should be taken care of
"date... (5 Replies)
Discussion started by: ektubbe
5 Replies
LEARN ABOUT DEBIAN
puzzle-diff
PUZZLE-DIFF(1)PUZZLE-DIFF(1)NAME
puzzle-diff - Compare pictures with libpuzzle
SYNOPSIS
[-b <contrast barrier for cropping>] [-c] [-C <max cropping ratio>] [-e] [-E <similarity threshold>] [-h] [-H <max height>] [-l <lambdas>]
[-n <noise cutoff>] [-p <p ratio>] [-t] [-W <max width>] <file 1> <file 2>
DESCRIPTION
puzzle-diff compares two pictures and outputs the normalized distance.
Try puzzle-diff -h for more info.
EXAMPLES
Output distance between two images:
$ puzzle-diff pic-a-0.jpg pics-a-1.jpg
0.102286
Compare two images, exit with 10 if they look the same, exit with 20 if they don't (may be useful for scripts):
$ puzzle-diff -e pic-a-0.jpg pics-a-1.jpg
$ echo $?
10
Compute distance, without cropping and with computing the average intensity of the whole blocks:
$ puzzle-diff -p 1.0 -c pic-a-0.jpg pic-a-1.jpg
0.0523151
AUTHORS
Frank DENIS libpuzzle at pureftpd dot org
SEE ALSO libpuzzle(3), puzzle_set(3)
2012-05-09 PUZZLE-DIFF(1)