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Full Discussion: Printing the differences
Top Forums Shell Programming and Scripting Printing the differences Post 302393279 by cmf1985 on Monday 8th of February 2010 09:59:19 AM
Old 02-08-2010
Maybe try this (I don't think elsif works in awk):
Code:
awk '{for(i=1; i<NF; i++) {if(($i-$(i+1)) < -10) {printf "-2 "} else if(($i-$(i+1)) > -10 && ($i-$(i+1)) <0) {printf "-1 "} else if(($i-$(i+1))>0 && ($i-$(i+1))<10) {printf "1 "} else {printf "2 "}}} {print "\n"}' inputfile > outputfile

 

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pnmpsnr(1)						      General Commands Manual							pnmpsnr(1)

NAME
pnmpsnr - compute the difference between two images (the PSNR) SYNOPSIS
pnmpsnr [pnmfile1] [pnmfile2] DESCRIPTION
Reads two PBM, PGM, or PPM files, or PAM equivalents, as input. Prints the peak signal-to-noise ratio (PSNR) difference between the two images. This metric is typically used in image compression papers to rate the distortion between original and decoded image. If the inputs are PBM or PGM, pnmpsnr prints the PSNR of the luminance only. Otherwise, it prints the separate PSNRs of the luminance, and chrominance (Cb and Cr) components of the colors. The PSNR of a given component is the ratio of the mean square difference of the component for the two images to the maximum mean square difference that can exist betwee any two images. It is expressed as a decibel value. The mean square difference of a component for two images is the mean square difference of the component value, comparing each pixel with the pixel in the same position of the other image. For the purposes of this computation, components are normalized to the scale [0..1]. The maximum mean square difference is identically 1. So the higher the PSNR, the closer the images are. A luminance PSNR of 20 means the mean square difference of the luminances of the pixels is 100 times less than the maximum possible difference, i.e. 0.01. SEE ALSO
pnm(5) 04 March 2001 pnmpsnr(1)
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