I'll make this short... Is there any good way to get the day number that first matches the Monday column from the cal command output with awk (or any other text manipulator commands) ?
Now, what I really need to get is the number of the first Monday in the month (I might also need, for example, the 3rd number of the Friday column, or any other number related to day that I need from that output).... In this case that would be the 7. I cannot think of anything since I have to consider that Monday might also be 1 or 2 in the 3rd line.....
Any idea?? I need this in order to setup a backup script for crontab, since as you know crontab is a little bit dumb.... but that doesn't matter.
Any help will be appreciated, thank you all in advance
Hi Gurus,
In my Cal output i want to cut the date of 2nd saturday how tyo achive this.
for eg in the below output i need that second saturday 13 to be cut.
crypto $ cal
January 2007
S M Tu W Th F S
1 2 3 4 5 6
7 8 9 10 11 12 13
14 15 16 17 18 19 20
21 22 23 24 25 26... (2 Replies)
Cal
Sun Mon Tue Wed Thu Fri Sat
1 2 3 4 5 6
7 8 9 10 11 12 13
14 15 16 17 18 19 20
21 22 23 24 25 26 27
28 29 30
cal | awk '{print $7}'
Sat
13
20
27
In the above output i am missing 6 because the first column is empty so it is shfting.
How... (3 Replies)
helo
i want to show today date and calendar when v succesfuly login on the system on the linux server
please orovide the sol for the same
thanx :):):) (1 Reply)
I have a script which archives log file events which are 90-days old. Script works fine but I wanted some input on one aspect of this script. My nawk statement, bolded below, that removes events 90-days prior from today, I need it to find anything 90-days or older. The log file date pattern looks... (0 Replies)
I have a function to center output in a terminal. However It only works for variables. I would like to center the output of the command 'cal' or 'cal -3' in a terminal.
I have tried:
center `cal`
CAL=`cal`; center $CAL
cal > cal.txt; center `cat cal.txt`
center "`exec cal`"
To no avail,... (10 Replies)
hi all
I would like to help me find the problem with this script to find and print to the screen a specific date of a log file that I have on my server, the date it is received as the first argument in the script $ 1
Here I show you a few lines that made the idea of my log file:
****... (4 Replies)
Hi All,
I'd like to create a specific output filename for AWK.
The file I am processing with AWK looks like:
output_081012.csv*
27*TEXT*1.0*2.0*3.0
where * is my delimeter and the first line of the file is the output filename i'd like to create
is there a way to assign an awk... (10 Replies)
Using the attached file, the below awk command results in the output below:
I can not seem to produce the desired results and need some expert help. Thank you :).
awk -F'' '
{
id += $4
value += $5
occur++
}
END{
printf "%-8s%8s%8s%8s\n", "Gene", "Targets", "Average Depth", "Average... (3 Replies)
In the below awk I am trying output to one file those lines that match between $2,$3,$4 of file1 and file2 with the count in (). I am also trying to output those lines that are missing between $2,$3,$4 of file1 and file2 with the count of in () each. Both input files are tab-delimited, but the... (7 Replies)
Discussion started by: cmccabe
7 Replies
LEARN ABOUT PHP
intlcalendar.getminimaldaysinfirstweek
INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3) 1 INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)IntlCalendar::getMinimalDaysInFirstWeek - Get minimal number of days the first week in a year or month can have
Object oriented style
SYNOPSIS
public int IntlCalendar::getMinimalDaysInFirstWeek (void )
DESCRIPTION
Procedural style
int intlcal_get_minimal_days_in_first_week (IntlCalendar $cal)
Returns the smallest number of days the first week of a year or month must have in the new year or month. For instance, in the Gregorian
calendar, if this value is 1, then the first week of the year will necessarily include January 1st, while if this value is 7, then the week
with January 1st will be the first week of the year only if the day of the week for January 1st matches the day of the week returned by
IntlCalendar.getFirstDayOfWeek(3); otherwise it will be the previous years last week.
PARAMETERS
o $cal
- The IntlCalendar resource.
RETURN VALUES
An int representing a number of days or FALSE on failure.
EXAMPLES
Example #1
IntlCalendar.getMinimalDaysInFirstWeek(3)
<?php
ini_set('date.timezone', 'UTC');
ini_set('intl.default_locale', 'en_US');
$cal = new IntlGregorianCalendar(2013, 0 /* January */, 2);
var_dump(IntlDateFormatter::formatObject($cal, 'cccc')); // Wednesday
var_dump($cal->getMinimalDaysInFirstWeek(), // 1
$cal->getFirstDayofWeek()); // 1 (Sunday)
// Week 1 of 2013
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
$cal->setMinimalDaysInFirstWeek(4);
// Still Week 1 of 2013 (1st week has 5 days in the new year)
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
$cal->setMinimalDaysInFirstWeek(6);
// Week 53 of 2012
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
The above example will output:
string(9) "Wednesday"
int(1)int(1)string(14) "Week 1 of 2013"
string(14) "Week 1 of 2013"
string(15) "Week 53 of 2012"
PHP Documentation Group INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)
12-16-2009
