12-03-2009
awk search column, print line
Hello.
I've been banging my head against walls trying to search a comma delimited file, using awk. I'm trying to search a "column" for a specific parameter, if it matches, then I'd like to print the whole line.
I've read in multiple texts:
awk -F, '{ if ($4 == "string") print $0 }' filename
OR
awk -F, '{ $4 == "string" }' filename
And nothing seems to work? What am I doing wrong?
Info:
OS - Ubuntu 9.10, using bash
BTW, this is my first post on these forums, please forgive any misused etc. etc.. I've been using these forums heavily to learn how to shell script etc.. This is an amazing community, us n00bs are lucky to have something like this. Thank you all so much.
If my question has been answered in another post (which I believe it has, but it didn't work see
https://www.unix.com/unix-dummies-que...int-lines.html )... please forgive me.
Thanks again
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COLRM(1) BSD General Commands Manual COLRM(1)
NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO
awk(1), column(1), cut(1), paste(1)
HISTORY
The colrm command appeared in 3.0BSD.
BSD
August 4, 2004 BSD