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Full Discussion: Passing Shell Input to AWK
Top Forums UNIX for Dummies Questions & Answers Passing Shell Input to AWK Post 302355408 by wawa44oz on Tuesday 22nd of September 2009 03:24:10 PM
Old 09-22-2009
Passing Shell Input to AWK
I am trying to search a log for a particluar pattern listing the total # of occurences in the end.

I thought using a shell script for input then calling awk to search for the paramters specified. I want the script to be usable acorss envs.

Code:
Code:
#! /usr/bin/bash
# get the variables
echo -n "1.  LogFILE ?"
read LOG
echo -n "2. SEARCH FOR ? "
read word
echo -n "3. Timestamp start = "
read time_st
echo -n "4. Timestamp end = "
read time_en
# search the file
awk  -v"1=${word}" "2=${time_st}" "3=${time_en}" "4=${log}" | wc


Source: Items in read is what I would like to search on.
Code:
10.7.90.85 - - [22/Sep/2009:10:02:24 -0400] "GET /portal/framework/skins/cafe/css/body.css HTTP/1.1" 200 1304
10.7.90.85 - - [22/Sep/2009:14:06:32 -0400] "GET /portal/cafekeepalive.jsp?NONE HTTP/1.1" 200 21

Output:
"CSS.sh" 12 lines, 287 characters
Code:
bash-3.00$  ./CSS.sh
1.  LogFILE ?log.log
2. SEARCH FOR ? cafe
3. Timestamp start = 10:0*
4. Timestamp end = 14:0*
awk: syntax error near line 1
awk: bailing out near line 1


Thanks in advance for any assitance
Last edited by vgersh99; 09-22-2009 at 04:40 PM.. Reason: code tags, PLEASE!
 

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