Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: Incrementing in while loop
Top Forums Shell Programming and Scripting Incrementing in while loop Post 302324044 by cfajohnson on Tuesday 9th of June 2009 06:24:01 PM
Old 06-09-2009
Quote:
Originally Posted by ultimatix
echo "Enter Starting id:"
echo ""
read rvst_strt_idxx
echo ""
echo "Enter Closing id:"
echo ""
read rvst_clsn_idxx

FIELD1=$rvst_strt_idxx
FIELD2="USER"
FIELD3="TEST"
FIELD4="12345"
FIELD5="00000"

echo ""
echo "INSERT INTO TABLE( FIELD1, FIELD2, FIELD3, FIELD4, FIELD5 ) "
echo " VALUES ( '$FIELD1','$FIELD2','$FIELD3','$FIELD4',$FIELD5') "


Suppose Starting id is 10 and closing Id is 20
I want to write a script which will increment the value of field1 in each loop starting with 10 and increment until 20 is reached

ie I need 20 lines of Insert into scripts which will have field1 values from 10 to 20

I think i need to write a while loop which increments the value of field 1 by 1 and until it reaches the upper limit is (20 here).

Please help

This will run in any standard Unix shell:

Code:
printf "Enter Starting id: "
read start
printf "Enter Closing id: "
read close

## You should first check that the user has entered valid numbers

FIELD2="USER" 
FIELD3="TEST"
FIELD4="12345"
FIELD5="00000"
n=$start
while [ $n -le $close ]
do
  FIELD1=$n
  echo "INSERT INTO TABLE( FIELD1, FIELD2, FIELD3, FIELD4, FIELD5 ) "
  printf " VALUES ( '%s','%s','%s','%s','%s') \
       "$FIELD1" "$FIELD2" "$FIELD3" "$FIELD4" "$FIELD5"
  n=$(( $n + 1 ))
done > output.sql

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

incrementing a for loop

I have, LIST="a b c d e" for word in $LIST do echo $word done would give me a b c d e With the first iteration of the for loop, I get "a" as the result. Is it possible that I get both "a" and "b" in only the first iteration. In the next iteration I get "c" and "d" and so on.... (2 Replies)
Discussion started by: run_time_error
2 Replies

2. Shell Programming and Scripting

New iteration of for-loop without incrementing?

Another question, is it possible to, in a for-loop incrementing until it reaches a certain number, to have it loop again without incrementing? Just have it drop what it is doing when it reaches this command and start again at the same number it was at? I know I could make a while loop and just... (0 Replies)
Discussion started by: jeriryan87
0 Replies

3. Post Here to Contact Site Administrators and Moderators

No. post not incrementing

Hi Admin, i just noticed that when I do postings, the number does not increment. eg : Post A -Total Posts 312 Post B - Total Posts 312 Post C - Total Posts 313 Post D - Total Posts 313 Why is this so? Can you kindly check this out? Thank you. (5 Replies)
Discussion started by: incredible
5 Replies

4. Shell Programming and Scripting

Need help with incrementing date in while loop.

I need to execute a KornShell (SunOS 5.9) script against a range of dates: endDate=20080804 extractDate=20080401 while ; do batch < scripts/myshellscript.sh $extractDate ## add 1 day to extractDate ## done My question is how do I increment the extractDate variable and still have it... (3 Replies)
Discussion started by: Robert W.Mills
3 Replies

5. Shell Programming and Scripting

Incrementing a variable is not happening

Hi All, Iam trying to increment a variable Following is the code #!/usr/bin/ksh i=1; i='expr $i+1'; echo $i; Output: expr $i+1 not able to understand why its happening in that way i was expecting result as 2... if the above method is worng .. can you help how i can get... (3 Replies)
Discussion started by: kiranlalka
3 Replies

6. Programming

incrementing variables in C++

Hello, what is the result of the below, and how does it work? int i = 5; cout << i++ * ++i << endl; cout << i << endl; (12 Replies)
Discussion started by: milhan
12 Replies

7. Homework & Coursework Questions

Incrementing Variable resets outside of while loop

1. The problem statement, all variables and given/known data: Variable is resetting to 0 after incrementing in while loop My bit of scripting displays the current users logged in the machine. Then it reads in a specific username and displays the processes for that user. The portion that I... (3 Replies)
Discussion started by: ratzlaff
3 Replies

8. Shell Programming and Scripting

Incrementing with a twist - please help

I'm currently trying to write a ksh or csh script that would change the name of a file found in directories and attach to the name an incrementing three digit number. I know how to write a script that will go: 000, 001, 002, 003, etc The twist is I need more increments then allowed by a 3... (11 Replies)
Discussion started by: Rust
11 Replies

9. UNIX for Dummies Questions & Answers

Incrementing variable in for

Hi, want to increment a variable in a for loop like this: for (( c=$total-1; c>=0; c-- )) do if ; then maximo=$valores fi done But it gives the error: No such file or directory How can i do this only incrementing the c variable? Thanks (8 Replies)
Discussion started by: limadario
8 Replies

10. UNIX for Dummies Questions & Answers

Help with incrementing the date

I have a date variable like 2012-12-31 ( YYYY -MM -DD ) in flat file and it has to be incremtented by 1 every time i run the script Example : i tried the below script after data modifcation but this does not seem to work expr `20121231 +%Y%m%d` + 1 Note : Mine is not a GNU... (4 Replies)
Discussion started by: akshay01987
4 Replies

LEARN ABOUT LINUX

shtool-echo

SHTOOL-ECHO.TMP(1)					      GNU Portable Shell Tool						SHTOOL-ECHO.TMP(1)

NAME

       shtool-echo - GNU shtool echo(1) extensional command

SYNOPSIS

       shtool echo [-n|--newline] [-e|--expand] string

DESCRIPTION

       shtool echo is an echo(1) style command which prints string to stdout and optionally provides special expansion constructs (terminal bold
       mode, environment details, date, etc) and newline control. The trick of this command is that it provides a portable -n option and hides the
       gory details needed to find out the environment details under option -e.

OPTIONS

       The following command line options are available.

       -n, --newline
	   By default, output is written to stdout followed by a "newline" (ASCII character 0x0a). If option -n is used, this newline character is
	   omitted.

       -e, --expand
	   If option -e is used, string can contain special "%x" constructs which are expanded before the output is written. Currently the
	   following constructs are recognized:

	   %B  switch terminal mode to bold display mode.

	   %b  switch terminal mode back to normal display mode.

	   %u  the current user name.

	   %U  the current user id (numerical).

	   %g  the current group name.

	   %G  the current group id (numerical).

	   %h  the current hostname (without any domain extension).

	   %d  the current domain name.

	   %D  the current day of the month.

	   %M  the current month (numerical).

	   %m  the current month name.

	   %Y  the current year.

EXAMPLE

	#   shell script
	shtool echo -n -e "Enter your name [%B%u%b]: "; read name
	shtool echo -e "Your Email address might be %u@%h%d"
	shtool echo -e "The current date is %D-%m-%Y"

HISTORY

       The GNU shtool echo command was originally written by Ralf S.  Engelschall <rse@engelschall.com> in 1998 for Website META Language (WML)
       under the name buildinfo. It was later taken over into GNU shtool.

SEE ALSO

       shtool(1), echo(1).

18-Jul-2008							   shtool 2.0.8 						SHTOOL-ECHO.TMP(1)
All times are GMT -4. The time now is 08:17 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy