05-26-2009
awk help in calulating difference for last two lines
Hi all,
I have a requirement for a script to find out the increase in memory. We have a log native_stderr.log where this will log.
bash-2.05$ tail -40 native_stderr.log | grep ': freed'
<GC(4140): freed 168190456 bytes, 66% free (180990488/271776256), in 253 ms>
<GC(4141): freed 167436384 bytes, 66% free (180290224/271776256), in 414 ms>
<GC(4142): freed 168588096 bytes, 66% free (181440728/271776256), in 352 ms>
Here i have put some more filter and able to get the values.
tail -40 native_stderr.log | grep ': freed' | awk -F '(' '{print $3}' | awk -F '/|)' '{print $1, $2}'
178893640 271776256
178153688 271776256
178595056 271776256
but i need to find out the differnce between the last line $1 value and the second last line value $1
like 178595056 - 178153688 = 441368 bytes
then change to MB 441368/(1024*1024) = 0.42
if this value is more than 50 MB then i need to send mail. Could you please some one help on this.
Thanks
Senthilkumar AK
-----Post Update-----
i have found some way but still your expert views needed on this
tail -40 native_stderr.log | grep ': freed' | awk -F '(' '{print $3}' | awk -F '/|)' '{a=($2-$1)/(1024*1024);y=x "\n" a; x=a};END{printf "%-15s%3.2f%-2s\n", "Difference is", x-y, " MB"}'
Thanks
Senthyilkumar
Last edited by senthilkumar_ak; 05-26-2009 at 06:12 PM..
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