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Top Forums Shell Programming and Scripting Error extracting 1 or more numbers with expr command Post 302312860 by fire! on Monday 4th of May 2009 12:12:39 AM
Old 05-04-2009
Error extracting 1 or more numbers with expr command

Need help with the following, I want to extract the digits from the following file pattern
using the expr command. digits are in the range 1-99

Tried two different methods, not sure what I am doing wrong.

file1=file1.dbf
file10=file10.dbf

Works for

expr "$file10" : '.*\([0-9][0-9]\)'
10

But not for

expr "$file1" : '.*\([0-9][0-9]\)'
<blank>

Tried to use the repitition operator but once again did not work as expected.
Incorrectly extracts the second digit only.

expr "$file10" : '.*\([0-9]\{1,2\}\)'
0

Repetition operator accepts the minimum value.
This was confirmed with the following ...

expr "$file10" : '.*\([0-9]\{2\}\)'
10
 

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EXPR(1) 						      General Commands Manual							   EXPR(1)

NAME
expr - evaluate arguments as an expression SYNOPSIS
expr arg ... DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is a separate argument. The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped. expr | expr yields the first expr if it is neither null nor `0', otherwise yields the second expr. expr & expr yields the first expr if neither expr is null or `0', otherwise yields `0'. expr relop expr where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if both expr are integers, otherwise lexicographic. expr + expr expr - expr addition or subtraction of the arguments. expr * expr expr / expr expr % expr multiplication, division, or remainder of the arguments. expr : expr The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the matching operator yields the number of characters matched (`0' on failure). ( expr ) parentheses for grouping. Examples: To add 1 to the Shell variable a: a=`expr $a + 1` To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/': expr $a : '.*/(.*)' '|' $a Note the quoted Shell metacharacters. SEE ALSO
sh(1), test(1) DIAGNOSTICS
Expr returns the following exit codes: 0 if the expression is neither null nor `0', 1 if the expression is null or `0', 2 for invalid expressions. 7th Edition April 29, 1985 EXPR(1)
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