04-21-2009
Quote:
Originally Posted by
ganapathi.t
var1="nbs2yth 3123 1 fsfsa thisissamletext"
echo $var1 | awk -F" " '{print $1}'
no need -F" "
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Greetings.
I am struggling with a shell script to make my life simpler, with a number of practical ways in which it could be used. I want to take a standard text file, and pull the 'n'th word from each line such as the first word from a text file.
I'm struggling to see how each line can be... (5 Replies)
Discussion started by: tricky
5 Replies
2. UNIX for Dummies Questions & Answers
Hey All,
On commad promt of a shell..
How can we move our cursor word by word.
Like Ctrl+A takes to the starting of the command...
Any shortcut like that..?
Thanks
pbsrinivas (1 Reply)
Discussion started by: pbsrinivas
1 Replies
3. Shell Programming and Scripting
i have this line
my,name,is,john
stored in a file d.sh and i wish to print the line as string..but im getting word by word...have tried this.........
for in $(cat $d.sh);
do
echo $i
done
but this is giving me
my
name
is
john (6 Replies)
Discussion started by: vadharah
6 Replies
4. UNIX for Dummies Questions & Answers
Assume I have a text file as below:
me
con pi
ind ken
pras ur
me
con rome
ind kent
pras urs
pintu
con mys
ind pan
pras ki
con kit
ind sys
My requirement,
I need to search for "con rome" and if exists, then print 4th word from rome, i.e in above example, since "con rome"... (4 Replies)
Discussion started by: jaggesh
4 Replies
5. Shell Programming and Scripting
Adding a word in front of a word of each line.In that line only one word will be there.
pl help:( (4 Replies)
Discussion started by: Ramesh Vellanki
4 Replies
6. UNIX for Dummies Questions & Answers
I have a File with the below contents
File1
I have no prior experience in unix. I have just started to work in unix.
My experience in unix is 0. My Total It exp is 3 yrs.
I need to replace the first word in each line with the last word for example
unix have no prior experience in... (2 Replies)
Discussion started by: kri_swami
2 Replies
7. Shell Programming and Scripting
i have a file in this pattern
MATCH1 word1 IMAGE word3 word4
MATCH2 word1 word2 word3 word4
MATCH2 word1 word2 word3 word4
MATCH2 word1 word2 word3 word4
MATCH2 word1 word2 word3 word4
MATCH1 word1 IMAGE word3 word4
MATCH2 word1 word2 word3 word4
MATCH2 word1 word2 word3 word4
MATCH2 word1... (7 Replies)
Discussion started by: bangaram
7 Replies
8. Shell Programming and Scripting
FOLKS ,
i have a text file that is generated automatically of an another korn shell script, i want to bring in the fifth line of the text file in to my korn shell script and look for a particular word in the line . Can you all share some thoughts on this one.
thanks...
Venu (3 Replies)
Discussion started by: venu
3 Replies
9. Shell Programming and Scripting
Hi All,
Hope you guys had a wonderful weekend
I have a scenario where in which I have to read a file line by line
and check for few words before redirecting to a file
I have searched the forum but,either those answers dint work (perhaps because of my wrong under standing of how IFS... (6 Replies)
Discussion started by: Kingcobra
6 Replies
10. Shell Programming and Scripting
I have a file: file.txt, which contains the following data in it.
This is a file, my name is Karl, what is this process, karl is karl junior, file is a test file, file's name is file.txt
My name is not Karl, my name is Karl Joey
What is your name?
Do you know your name and... (3 Replies)
Discussion started by: anuragpgtgerman
3 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)
debug_zval_dump - Dumps a string representation of an internal zend value to output
SYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO
var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)