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Top Forums Programming sizeof an array of structure without using 'sizeof' operator Post 302302459 by pshaikh on Tuesday 31st of March 2009 04:00:30 AM
Old 03-31-2009
Quote:
But if i try to subtract address of say &array[1] - &array[0] doesn't give the sizeof the array instead it gives 1 always. I just tried printing &array[1] and &array[0] which gives the address. When we subtract the address of begin and end variable it gives the number of bytes occupied between those two and why not in &array[1] - &array[0]. Kindly clarify.
This is because, compiler 'knows' type of array and it places instructions of pointer arithmetic using size of 'type'.

so &array[1] - &array[0] = number of elements of type of 'array' between &array[1] and &array[0]

Try this (char*)&array[1] - (char*)&array[0] or (unsigned long)(&array[1]) - (unsigned long)(&array[0])
 

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RESET(3)								 1								  RESET(3)

reset - Set the internal pointer of an array to its first element

SYNOPSIS
mixed reset (array &$array) DESCRIPTION
reset(3) rewinds $array's internal pointer to the first element and returns the value of the first array element. PARAMETERS
o $array - The input array. RETURN VALUES
Returns the value of the first array element, or FALSE if the array is empty. EXAMPLES
Example #1 reset(3) example <?php $array = array('step one', 'step two', 'step three', 'step four'); // by default, the pointer is on the first element echo current($array) . "<br /> "; // "step one" // skip two steps next($array); next($array); echo current($array) . "<br /> "; // "step three" // reset pointer, start again on step one reset($array); echo current($array) . "<br /> "; // "step one" ?> SEE ALSO
current(3), each(3), end(3), next(3), prev(3). PHP Documentation Group RESET(3)
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