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Full Discussion: Echo behavior
Top Forums Shell Programming and Scripting Echo behavior Post 302285955 by Corona688 on Tuesday 10th of February 2009 02:28:28 AM
Old 02-10-2009
Quote:
Originally Posted by Saurabh78
Echo is removing extra blank spaces. See the command.

export INSTALLDIR=”First Second /Two Space”
First off, the two spaces aren't visible unless you put code in code tags. [ code ] stuff [ /code ] without the extra spaces in the tags.

And the reason that the extra space is lost is because the shell splits commands apart on spaces, even if they're a single variable, nothing to do with echo. Your command, without the quotes, amounts to:

Code:
echo "First" "Second "/Two" "space"

You use quotes to tell the shell not to split a string apart.
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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