11-13-2008
Try this :)
perl -e "$var=help"; -e "print unpack 'H*',$var"
68656c70
I think in your previous case the instance of the variable is lost if u r invoking the statements individually.(correct me if am wrong)
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LEARN ABOUT PHP
is_scalar
IS_SCALAR(3) 1 IS_SCALAR(3)
is_scalar - Finds whether a variable is a scalar
SYNOPSIS
bool is_scalar (mixed $var)
DESCRIPTION
Finds whether the given variable is a scalar.
Scalar variables are those containing an integer, float, string or boolean. Types array, object and resource are not scalar.
Note
is_scalar(3) does not consider resource type values to be scalar as resources are abstract datatypes which are currently based on
integers. This implementation detail should not be relied upon, as it may change.
Note
is_scalar(3) does not consider NULL to be scalar.
PARAMETERS
o $var
- The variable being evaluated.
RETURN VALUES
Returns TRUE if $var is a scalar, FALSE otherwise.
EXAMPLES
Example #1
is_scalar(3) example
<?php
function show_var($var)
{
if (is_scalar($var)) {
echo $var;
} else {
var_dump($var);
}
}
$pi = 3.1416;
$proteins = array("hemoglobin", "cytochrome c oxidase", "ferredoxin");
show_var($pi);
show_var($proteins)
?>
The above example will output:
3.1416
array(3) {
[0]=>
string(10) "hemoglobin"
[1]=>
string(20) "cytochrome c oxidase"
[2]=>
string(10) "ferredoxin"
}
SEE ALSO
is_float(3), is_int(3), is_numeric(3), is_real(3), is_string(3), is_bool(3), is_object(3), is_array(3).
PHP Documentation Group IS_SCALAR(3)