Hi!
I've the following script code with an input parameter:
sed 's/oldstring/$1/g' myfile > newfile
(I launch it with comman line: $ MyShell newstring)
Problem: the substituion doesn't work (oldstring becomes $1, instead of newstring). How could I solve this situation?
Thanks, ... (2 Replies)
When I run the script I pass in 2 expressions (ex. replace.ksh new old)
I want the script to go line by line for a given file in a given directory and replace the word new with old. Of course in my line where I have the awk statement it is replacing the 2nd word with 1st instead of new with... (3 Replies)
Hello
I have several files where a string similar to this appears:
/home/workload/bin/ProcDly/scrpts/T54.sh > $LOG
I need to change it to something like this:
$VARIABLE > $LOG
However, due to the configuration of the rest of the files, I should only find this string by the... (4 Replies)
Hey ppl,
Could u tell me how to replace such a string
xyz->x with XYZ(x), where x can be any variable accessible by pointer to structure, xyz
in an entire file? (1 Reply)
Hey ppl,
Could u tell me how to replace such a string
xyz->x with XYZ(x), where x can be any variable accessible by pointer to structure, xyz
in an entire file? (3 Replies)
Hi friends!
I have a tab delimited file with two columns :
GB_45_DRB SP:0139466(mrmi sisignm)|SP:3674(fllflg_itoioh)|SP:68954779(RMTKLGF to emmdm-roomto)
GB_45_DRD SP:475928(mgmdksi rikgkg)|SP:587959(roykgl tiic-tm)|SP:0139466(mrmi sisignm)|SP:3674(fllflg_itoioh)|SP:68954779(RMTKLGF to... (4 Replies)
hi guys...need some help here...
i am making a a script to automatically install netbackup client...so its gonna write a configuration file according to the host name.... the line would be something like this
CLIENT_NAME = odel_bkp.test.com
the thing is ...the host name in reallity is... (2 Replies)
Hi,
I have a template file and want to replace 3 parameters to the values that I want. these values are in a parameter file.
Any idea how to do this in perl?
the parameter file looks like:
host_name = jupiter
PORT = 1562
IPADDRESS = 10.1.34.10
the template file has lots of entry.... (1 Reply)
I have the following code:
strfuture=abcdefghi
ver=${strfuture:${count}:1}
mj7777_ver=${ver} start_mj7777_iteration
let count=count+1
When it is executed I get bad substitution. The same if I use
ver=${strfuture:$count:1}
mj7777_ver=${ver}... (6 Replies)
We have a formatted screen system where a driver program passes the locations of a list of files that called programs may be using. It will look something like this:
/{number of characters varies}/DATA/MASTERFILEBecause of the size of some files we will be splitting older records into a history... (2 Replies)
Discussion started by: wbport
2 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)