Sponsored Content
Top Forums Shell Programming and Scripting Adding delimiter to logged in users Post 302232221 by era on Thursday 4th of September 2008 06:18:32 AM
Old 09-04-2008
It's basically equivalent to awk -v user="$f" -F : '$1 == user { print $5 }' if you prefer that. It prints the fifth field when there is a match on the first. (The sed script additionally prunes anything after the first comma; you can do that with sub in awk.)

Actually this could be a place to finally actually implement the putting of pipes between the values!

Code:
awk -v regex=^`echo -n "$users"*| tr ' ' '|'`$ -F : '
  $1 ~ regex { p=$5; sub (/,.*/, "", p); print p " has logged in more than once" }' /etc/passwd

If your awk doesn't understand -v, see if you have nawk or gawk or mawk

Last edited by era; 09-04-2008 at 07:25 AM.. Reason: Finally implement pipes between values
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Information about users who have logged.

Hi, Suppose I have a programme called Menu. This menu has various choices as we would expect from a Menu. Now Can you Please help me as I want the details of the Users to be registered to some file , Whoever has entered this particular Program . Basically to see the username and the time that... (2 Replies)
Discussion started by: rooh
2 Replies

2. Shell Programming and Scripting

how many users logged

in unix what is the syntax to find out how many users are currently logged in (4 Replies)
Discussion started by: trichyselva
4 Replies

3. UNIX for Advanced & Expert Users

HP-UX users get logged off while idle.

Im "supporting" at least 2500 HP-UX workstations with CAD-related software with the B.11.11 build. I cant say anymore than that because of my companys sligtly paranoid security policy . The last few days a new problem has arised from nowhere. The problem is that users gets logged off when the... (5 Replies)
Discussion started by: Laoinjo
5 Replies

4. Post Here to Contact Site Administrators and Moderators

logged out users

how to find out users who logged out within 5 minutes (1 Reply)
Discussion started by: roshni
1 Replies

5. Shell Programming and Scripting

Users Not Logged in

I have searched the forums but have not mangaed to quite find what im looking for. I have used to /etc/passwd command to present me a list of all users the who command to present all users currently logged on, but what i want to know is what command can i use to display users that are registered... (12 Replies)
Discussion started by: warlock129
12 Replies

6. Programming

Get the list of logged in users

How can I get the list of logged in users in the system programmatically? I can get the list with 'who' or 'users' commands but I need to get the list programmatically... May someone help, please? Thanks in advance. (2 Replies)
Discussion started by: xyzt
2 Replies

7. UNIX for Dummies Questions & Answers

How many users are logged in?

How do I find this out? I have a feeling its a simple command such as who, but I just don't know what it is. I've had a search on here but either I can't put it into the right search criteria or there isn't a topic on it. Thanks. EDIT: Delete this thread, as I posted it I noticed the... (0 Replies)
Discussion started by: chris_rabz
0 Replies

8. Red Hat

Current logged in users

I have 2 systems. (1) RHEL5 and (2) winXP pro from xpPRO putty i ssh into rhel5 : user root from xpPRO i ftp into rhel5 : user abc123 when i run #uptime it only shows 1 user when i do #ps -u abc123 : it shows vsftpd deamon PID is there a command that can be used to show all currently... (4 Replies)
Discussion started by: dplinux
4 Replies

9. Shell Programming and Scripting

Users not logged in for last 90 days

Hi, How to find the users who did not login into a UNIX box (thru ssh/ftp or any other way) for last 90 days? I think of using "finger" or "last" command to findout each user's last login and then find number of days between today and that day. Is there any other better way or anyone prepared... (1 Reply)
Discussion started by: reddyr
1 Replies

10. UNIX for Dummies Questions & Answers

Users logged into the system

So I'm trying to write a single line command So I have to use last first in this command and I've figured out the format my professor wants it in, something like thislast | cut -d' ' -f1,15 | sort > check | uniq -c.... and I never can get it right, when I just last command I get something... (2 Replies)
Discussion started by: DoubleAlpha
2 Replies
qmail-pw2u(8)						      System Manager's Manual						     qmail-pw2u(8)

NAME
qmail-pw2u - build address assignments from a passwd file SYNOPSIS
qmail-pw2u [ -/ohHuUC ] [ -cchar ] DESCRIPTION
qmail-pw2u reads a V7-format passwd file from standard input and prints a qmail-users-format assignment file. A V7-format passwd file is a series of lines. Each line has the format user:password:uid:gid:gecos:home:shell where user is an account name, uid and gid are the user id and group id of that account, and home is the account's home directory. pass- word, gecos, and shell are ignored by qmail-pw2u. If you put the output of qmail-pw2u into /var/lib/qmail/users/assign, and then run qmail-newu, qmail-lspawn will obey the assignments printed by qmail-pw2u. WARNING: After changing any users, uids, gids, or home directories in your passwd file, you must run qmail-pw2u and qmail-newu again if you want qmail-lspawn to see the changes. RULES
By default, qmail-pw2u follows the same rules as qmail-getpw. It skips user if (1) uid is zero, (2) home does not exist, (3) user does not own home, or (4) user contains uppercase letters. It then gives each remaining user control over the basic user address and all addresses of the form user-anything. A catch-all user, alias, controls all other addresses. You may change these rules by setting up files in /var/lib/qmail/users: include Allowed users, one per line. If include exists, and user is not listed in include, user is ignored. exclude Ignored users, one per line. If exclude exists, and user is listed in exclude, user is ignored. mailnames Replacement names for users. Each line has the form user:mailname1:mailname2:... The addresses mailname1 and mailname1-ext and mailname2 and so on will be delivered to user. WARNING: The addresses user and user-ext will not be delivered to user unless user is listed as one of the mailnames. A line in mailnames is silently ignored if the user does not exist. subusers Extra addresses. Each line has the form sub:user:pre: sub will be handled by home/.qmail-pre, where home is user's home directory; sub-ext will be handled by home/.qmail-pre-ext. append Extra assignments, printed at the end of qmail-pw2u's output. OPTIONS
-o (Default.) Skip user if home does not exist (or is not visible to qmail-pw2u). Skip user if home is not owned by user. -h Stop if home does not exist. This is appropriate if every user is supposed to have a home directory. Skip user if home is not owned by user. -H Do not check the existence or ownership of home. -U (Default.) Skip user if there are any uppercase letters in user. -u Allow uppercase letters in user. -cchar Use char as the user-extension delimiter in place of -. -C Disable the user-extension mechanism. -/ Use home/.qmail-/... instead of home/.qmail-... SEE ALSO
qmail-users(5), qmail-lspawn(8), qmail-newu(8), qmail-getpw(8) qmail-pw2u(8)
All times are GMT -4. The time now is 12:00 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy