Hi,
How to separate numbers and words(with full alphabets) in a particular file and store it in two different files.
Please help me out for this.Using shell scripting.
:confused::confused: (1 Reply)
Hi all,
Please some help over here. I have a Sales.txt file containing info in blocks for
every sold product in the pattern showed below (only for 2 products).
NEW BLOCK
SALE DATA
PRODUCT SERIAL
79833269999 146701011945004
.Some other data
.Some... (17 Replies)
Hi,
I have to write a shell script that converts numbers in to words
below is what i wrote.My script is not running.
-----------------------------------
echo -n "Enter number : "
read n
len= echo $n | wc -c
echo " number in words : "
for ( i=1; i<len; i++ )
do
num=echo $n... (5 Replies)
Hi guys,
I have got a file which doesn't have the same number of columns in each line. I would like to print the second column and the one that begins with 33= and has some numbers after '33='
Can you please help me asap?
Cheers (7 Replies)
Hi All,
I have searched the forum and tried to print only matching(pattern) words from the file, but its printing entire line. I tried with grep -w. I am on sunsolaris.
Eg:
cat file
A|A|F1|F2|A|F3|A
A|F10|F11|F14|A|
F20|A|F21|A|F25
I have to search for F (F followed by numbers) and ... (5 Replies)
Hi,
Sorry in advance for propably a silly question, but I am a bit lost.
On some of the linux job flow I have the following check:
if ($file != 1500) then
echo ERROR
It works ok, all times $file is not equal to 1500 I have the error message.
I try to do something similar... (7 Replies)
Hi. I have a file containing words and numbers associated with them as follows -
c 2
b 5
c 5
b 6
a 10
b 16
c 18
a 19
b 21
c 27
a 28
b 33
a 76
a 115
c 199
c 251
a 567
a 1909 (4 Replies)
Hi All,
I tried to solve this but the result gives me all zeros for one file. I failed to do for all 500 files.
I have some 500 files with the extension .dat I have another set of files; 500 in number with extension .dic I created these .dic files by using sort -u from the actual .dat files.... (2 Replies)
Hi All,
I have a file which looks like this:
abc 1
abc 2
abc 3
abc 4
abc 5
bcd 1
bcd 3
bcd 3
bcd 5
cde 7
This file is just a miniature version of what I really have. Original file is some 1 million lines long.
I have tried to come up with the code for what I wish to accomplish... (1 Reply)
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)