Sponsored Content
Top Forums UNIX for Dummies Questions & Answers joining variable to the end of a file name Post 302221246 by naamas03 on Monday 4th of August 2008 03:48:22 AM
Old 08-04-2008
hi
thanks for quick response
i did like you've wrote
here are the result
sed: -e expression #1, char 57: Unmatched ) or \)
it's an error
can you please tell me what is wrong
and please a little explanation about the command.
thanks
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Joining lines in log file

Hi, I need to develop a script to join multiple three lines in a log file into one line for processing with awk and grep. I looked at tr with no success. The first line contains the date time information. The second line contains the error line. The third line is a blank line. Thanks, Mike (3 Replies)
Discussion started by: bubba112557
3 Replies

2. Shell Programming and Scripting

Joining 2 lines in a file together

Hi guys, I've got a log file which has entries that look like this: ------------------------------------------------------------------------------- 06/08/04 07:57:57 AMQ9002: Channel program started. EXPLANATION: Channel program 'INSCCPQ1.HSMTSPQ1' started. ACTION: None. ... (3 Replies)
Discussion started by: m223464
3 Replies

3. Shell Programming and Scripting

Joining program to one batch file

I created a batch file (./mybatch) that need to run few programs at a sequnece but i need a command like the DOS call command in order to return to the main batch file to proceed the sequence example: cd /dir1/path/dir2 invoke program1 cd /dir3/path2/ <--- i want to return here (2 Replies)
Discussion started by: eynkesef
2 Replies

4. Shell Programming and Scripting

Joining two arrays and then creating a variable

Hello all... I'd like to create a variable from an array element from two arrays. In my search for answers I found this code for bash that joins two arrays and then started to work with it. I had got to work once and then foolishly without saving the code, I started to edit it for ksh and... (4 Replies)
Discussion started by: carlos25
4 Replies

5. Shell Programming and Scripting

Add end of char \n on end of file

Hi, I want to add \n as a EOF at the end of file if it does't exist in a single command. How to do this? when I use command echo "1\n" > a.txt and od -c a.txt 0000000 1 \n \n 0000003 How does it differentiate \n and eof in this case? Regards, Venkat (1 Reply)
Discussion started by: svenkatareddy
1 Replies

6. Shell Programming and Scripting

variable joining

I really need help on this problem. The story: My VAR1 and VAR2 works fine and able to get the value. I want to do as "if VAR1 or VAR2 is bigger than max_loadavg then the code will run...then if VAR1 or VAR2 is lesser than min_loadavg then the other code will run... The problem: The... (8 Replies)
Discussion started by: hezry79
8 Replies

7. Shell Programming and Scripting

Appending string, variable to file at the start and string at end

Hi , I have below file with 13 columns. I need 2-13 columns seperated by comma and I want to append each row with a string "INSERT INTO xxx" in the begining as 1st column and then a variable "$node" and then $2,$3,$4,$5,$6,$7,$8,$9,$10,$11,$12,$13 and at the end another string " ; COMMIT;" ... (4 Replies)
Discussion started by: Vaddadi
4 Replies

8. Shell Programming and Scripting

bash - joining lines in a file

I’m writing a bash shell script and I want to join lines together where two variables on each line are the same ie. 12345variablestuff43212morevariablestuff 12345variablestuff43212morevariablestuff 34657variablestuff78945morevariablestuff 34657variablestuff78945morevariablestuff... (12 Replies)
Discussion started by: Cultcha
12 Replies

9. Shell Programming and Scripting

Joining lines in a file - help!

I'm looking for a way to join lines in a file; e.,g consider the following R|This is line 1 R|This is line 2 R|This is line 3 R|This is line 4 R|This is line 5 what i want to end up with is R|This is line 1 R|This is line 2 R|This is line 3 R|This is line 4 R|This is line 5 so... (15 Replies)
Discussion started by: Storms
15 Replies

10. UNIX for Dummies Questions & Answers

File joining and sorting

Hi, I'm having some trouble joining these two files for some reason. Here is what they look like: head * I'm using: join -a 1 -1 2 -2 1 f1 f2 -t, > joinfile.out but unfortunately nothing is happening. I did notice that I was having trouble sorting f1 and I'm not sure why using:... (6 Replies)
Discussion started by: verse123
6 Replies
regexpr(3GEN)					     String Pattern-Matching Library Functions					     regexpr(3GEN)

NAME
regexpr, compile, step, advance - regular expression compile and match routines SYNOPSIS
cc [flag]... [file]... -lgen [library]... #include <regexpr.h> char *compile(char *instring, char *expbuf, const char *endbuf); int step(const char *string, const char *expbuf); int advance(const char *string, const char *expbuf); extern char *loc1, loc2, locs; extern int nbra, regerrno, reglength; extern char *braslist[], *braelist[]; DESCRIPTION
These routines are used to compile regular expressions and match the compiled expressions against lines. The regular expressions compiled are in the form used by ed(1). The parameter instring is a null-terminated string representing the regular expression. The parameter expbuf points to the place where the compiled regular expression is to be placed. If expbuf is NULL, compile() uses mal- loc(3C) to allocate the space for the compiled regular expression. If an error occurs, this space is freed. It is the user's responsibil- ity to free unneeded space after the compiled regular expression is no longer needed. The parameter endbuf is one more than the highest address where the compiled regular expression may be placed. This argument is ignored if expbuf is NULL. If the compiled expression cannot fit in (endbuf-expbuf) bytes, compile() returns NULL and regerrno (see below) is set to 50. The parameter string is a pointer to a string of characters to be checked for a match. This string should be null-terminated. The parameter expbuf is the compiled regular expression obtained by a call of the function compile(). The function step() returns non-zero if the given string matches the regular expression, and zero if the expressions do not match. If there is a match, two external character pointers are set as a side effect to the call to step(). The variables set in step() are loc1 and loc2. loc1 is a pointer to the first character that matched the regular expression. The variable loc2 points to the character after the last character that matches the regular expression. Thus if the regular expression matches the entire line, loc1 points to the first char- acter of string and loc2 points to the null at the end of string. The purpose of step() is to step through the string argument until a match is found or until the end of string is reached. If the regular expression begins with ^, step() tries to match the regular expression at the beginning of the string only. The advance() function is similar to step(); but, it only sets the variable loc2 and always restricts matches to the beginning of the string. If one is looking for successive matches in the same string of characters, locs should be set equal to loc2, and step() should be called with string equal to loc2. locs is used by commands like ed and sed so that global substitutions like s/y*//g do not loop forever, and is NULL by default. The external variable nbra is used to determine the number of subexpressions in the compiled regular expression. braslist and braelist are arrays of character pointers that point to the start and end of the nbra subexpressions in the matched string. For example, after calling step() or advance() with string sabcdefg and regular expression (abcdef), braslist[0] will point at a and braelist[0] will point at g. These arrays are used by commands like ed and sed for substitute replacement patterns that contain the notation for subexpressions. Note that it is not necessary to use the external variables regerrno, nbra, loc1, loc2 locs, braelist, and braslist if one is only checking whether or not a string matches a regular expression. EXAMPLES
Example 1 The following is similar to the regular expression code from grep: #include<regexpr.h> . . . if(compile(*argv, (char *)0, (char *)0) == (char *)0) regerr(regerrno); . . . if (step(linebuf, expbuf)) succeed(); RETURN VALUES
If compile() succeeds, it returns a non-NULL pointer whose value depends on expbuf. If expbuf is non-NULL, compile() returns a pointer to the byte after the last byte in the compiled regular expression. The length of the compiled regular expression is stored in reglength. Otherwise, compile() returns a pointer to the space allocated by malloc(3C). The functions step() and advance() return non-zero if the given string matches the regular expression, and zero if the expressions do not match. ERRORS
If an error is detected when compiling the regular expression, a NULL pointer is returned from compile() and regerrno is set to one of the non-zero error numbers indicated below: ERROR MEANING 11 Range endpoint too large. 16 Bad Number. 25 "digit" out or range. 36 Illegal or missing delimiter. 41 No remembered string search. 42 (~) imbalance. 43 Too many (. 44 More than 2 numbers given in [~}. 45 } expected after . 46 First number exceeds second in {~}. 49 [] imbalance. 50 Regular expression overflow. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |MT-Level |MT-Safe | +-----------------------------+-----------------------------+ SEE ALSO
ed(1), grep(1), sed(1), malloc(3C), attributes(5), regexp(5) NOTES
When compiling multi-threaded applications, the _REENTRANT flag must be defined on the compile line. This flag should only be used in multi-threaded applications. SunOS 5.11 29 Dec 1996 regexpr(3GEN)
All times are GMT -4. The time now is 07:22 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy