Sponsored Content
Top Forums Shell Programming and Scripting Snytax error on If Statement--help Post 302192798 by dannyd_y on Wednesday 7th of May 2008 10:47:15 PM
Old 05-07-2008
Ok i've fixed

year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`

case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12)
if [ $day = 7 ]
then
$day=6
fi
;;

4 | 6 | 9 | 11)
if [ $day = 0 ]
then
$day=31
fi
;;

2)
if [ $day = 0 ]
then
if [ `expr $year % 4` -eq 0]
then
$day = 28
else
$day = 29
fi
fi
;;
*) echo error: Case Statement Not Run ;;
esac

DATE=$year$month$day
cp $HOME/*$DATE*log $HOME/QVGLog
cd $HOME/QVGLog
gzip *


now the problem is the case statement failed, the message is
error: Case Statement Not Run
cp: cannot stat `/sgxde/sgxaspecs7/*2008057*log': No such file or directory
gzip: *: No such file or directory


Smilie
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

parsing error in if statement

hello, I am trying to parse an error returned by a command inside the if statement but it is just displays the full error instead and then stops. if ; then echo "no such package" else echo "similar version found will use pkgrm" fi the above code just displays please let me know... (2 Replies)
Discussion started by: rakeshou
2 Replies

2. Shell Programming and Scripting

Error with if statement..Please help

:b:hi, I have a script as given below: pr_det="1" if then awk ' BEGIN {printf("%23s","session")}' >> report.txt awk ' BEGIN {printf "\n"} ' >> report.txt else awk ' BEGIN {printf("%55s","file_dsc")} ' >> report.txt awk ' BEGIN {printf("%101s","no_recs")} '... (1 Reply)
Discussion started by: jisha
1 Replies

3. Linux

error in if statement

Hi , I am getting an error when I run the script for checking word "view" in a file . I am using if statement. like this if then VW_VAR=` cat $TN.${ecmdate}.sql1 | grep -i view | awk '{print $3}' | cut -d '.' -f2 ` echo " VW_$VW_VAR " sed -e... (16 Replies)
Discussion started by: capri_drm
16 Replies

4. Shell Programming and Scripting

Error in IF statement

HI i am getting error while executing the given statement for filename in `cat a/file.lst` do if then echo "Exit Code Description :File $filename - is missing in Input Directory" >a.log exit else count1=`awk 'END {print NR}' $filename` echo "$count1">>a.log count2=`awk 'END {print... (4 Replies)
Discussion started by: ravi214u
4 Replies

5. Shell Programming and Scripting

error in insert statement

hi, When i try to run the code below, i get the following error "ksh: syntax error: `(' unexpected" i am not able to figure it out. Can anyone help me? Code: (2 Replies)
Discussion started by: ragavhere
2 Replies

6. UNIX for Dummies Questions & Answers

error in if statement

Hi, This is my script to catch any oracle errors. In this, the $sqlerr returns ORA-01017: invalid username/password; logon denied when i specify wrong username/password the if condition is failing. how can i resolve the issue. the if statement gives error sqloutput=`sqlplus -s -L... (1 Reply)
Discussion started by: Swapna173
1 Replies

7. Shell Programming and Scripting

Error in if statement

I am working on script for stale nfs. the file consists of cat data01stale.log - - - - /abcd/backup - - - - /abcd/data Script (16 Replies)
Discussion started by: nareshkumar522
16 Replies

8. Shell Programming and Scripting

If statement Syntax error

Hi Can you please tell me what is wrong with this line: if && ]; then basically i want to check if x = 12 and F (Filename) end with 'g'. But it is throwing syntax error. (7 Replies)
Discussion started by: rtagarra
7 Replies

9. Shell Programming and Scripting

Awk/if statement error

Can anybody tell the correct way to use the following awk pattern check within an if statement? When I run this command outside of the if statement cat /tmp/test2.out | awk -v T=$TIME -v G=$GROUP -v C=$CDATE '$0 ~ T && $0 ~ G && $0 ~ C' | grep -i "Starting the group" I get the following... (0 Replies)
Discussion started by: kieranfoley
0 Replies

10. UNIX for Beginners Questions & Answers

Error code with if statement

hello all im new to unix and when i use below script i get an error : #! /bin/bash Echo -e "enter the name of the file : \c" read file_name if then echo "$file_name found" else echo "$file_name not found" fi running the script i get below error : $ ./hello (26 Replies)
Discussion started by: Ibrahims1
26 Replies
XCALPR(1)						      General Commands Manual							 XCALPR(1)

NAME
xcalpr - print xcal calendar entries SYNTAX
xcalpr [ -c ][ -x ][ -f file ][ -d dir ][ -u user ][ date-spec ] DESCRIPTION
Xcalpr prints the contents of the xcal files. It is intended to be used in situations when you have no access to an X screen. It can also be used to generate entries for the standard UNIX calendar program. With no arguments, it prints any entries that exist for the next seven days. The program also reads the contents of the seven daily files and prints them at the appropriate point in the output stream. Each line in the output is preceded by the day of the week, the day of the month, the month and the year. Xcalpr can be given a date specification to select months and years. If the date spec consists of just a year number, then all the data for that year is printed. For example: xcalpr 1994 will print all the data for 1994. Several years can be specified. If you give the name of a month, then the data for that month in the current year will be printed. If the month is in the past, then the data for that month next year will be printed. For example, if xcalpr oct jan is typed in August, xcalpr will print October in the current year and January next year. You can select a particular year by adding the number after any months that you need printing: xcalpr oct nov 1994 will print October and November in 1994. There are a couple of special `month' names. The name rest will print the data for the rest of the month, starting tomorrow. The rest argument is not recognised if you give a year as a parameter. If tomorrow happens to be the first day of the next month, then all the data for next month will be printed. The name next prints all the data for next month. OPTIONS
The -c option causes xcalpr to output lines suitable for input to the standard UNIX calendar program. The -d switch is followed by a directory name and specifies an alterative location for your Calendar directory. Your home directory is prepended if the name doesn't start with a slash or a dot. The -f option is followed by a file name and xcalpr will write it's output to that file, rather than standard output. The -u option is followed by a user name and dumps their calendar files rather than yours. The -x option makes xcalev operate with Calendar files that are compatible with the xcalendar program. FILES
$HOME/Calendar/* xc<dd><Mon><Year> A data file is day, Month in three letter format and the year. xy<Year> A year directory. xw<Day> A data file for the weekly code, one per day. SEE ALSO
xcal(1), xcalev(1), xcal_cal(1) AUTHOR
Copyright 1993 by Peter Collinson, Hillside Systems All rights reserved. This product includes software developed by the University of California, Berkeley and its contributors. X Version 11 R5 October 1993 XCALPR(1)
All times are GMT -4. The time now is 12:56 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy