parsing error in if statement


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# 1  
parsing error in if statement

hello,

I am trying to parse an error returned by a command inside the if statement but it is just displays the full error instead and then stops.

Code:
if [ `pkginfo xxx | grep "was not found"` ]; then
echo "no such package"
else
echo "similar version found will use pkgrm"
fi

the above code just displays

Quote:
ERROR: ERROR: information for "xxx" was not found
please let me know how can I parse the error message returned by a command inside the if statement.

Thanks
# 2  
Quote:
Originally Posted by rakeshou
hello,

I am trying to parse an error returned by a command inside the if statement but it is just displays the full error instead and then stops.


the above code just displays



please let me know how can I parse the error message returned by a command inside the if statement.

Thanks
Your back quotes just turn the output of the command into a string.

Try

Code:
pkginfo xxx | grep "was not found"

if test "$?" = "0" ; then
echo "no such package"
else
echo "similar version found will use pkgrm"
fi

# 3  
Quote:
Originally Posted by porter
Code:
pkginfo xxx | grep "was not found"

A minor correction. I think part of the problem is that the message is going to stderr and not stdout. It should be

Code:
pkginfo xxx 2>&1 | grep "was not found"


Last edited by kahuna; 09-25-2007 at 12:53 PM..
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