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Top Forums Shell Programming and Scripting Snytax error on If Statement--help Post 302192798 by dannyd_y on Wednesday 7th of May 2008 10:47:15 PM
Old 05-07-2008
Ok i've fixed

year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`

case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12)
if [ $day = 7 ]
then
$day=6
fi
;;

4 | 6 | 9 | 11)
if [ $day = 0 ]
then
$day=31
fi
;;

2)
if [ $day = 0 ]
then
if [ `expr $year % 4` -eq 0]
then
$day = 28
else
$day = 29
fi
fi
;;
*) echo error: Case Statement Not Run ;;
esac

DATE=$year$month$day
cp $HOME/*$DATE*log $HOME/QVGLog
cd $HOME/QVGLog
gzip *


now the problem is the case statement failed, the message is
error: Case Statement Not Run
cp: cannot stat `/sgxde/sgxaspecs7/*2008057*log': No such file or directory
gzip: *: No such file or directory


Smilie
 

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CAL_TO_JD(3)								 1							      CAL_TO_JD(3)

cal_to_jd - Converts from a supported calendar to Julian Day Count

SYNOPSIS
int cal_to_jd (int $calendar, int $month, int $day, int $year) DESCRIPTION
cal_to_jd(3) calculates the Julian day count for a date in the specified $calendar. Supported $calendars are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $calendar - Calendar to convert from, one of CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH or CAL_FRENCH. o $month - The month as a number, the valid range depends on the $calendar o $day - The day as a number, the valid range depends on the $calendar o $year - The year as a number, the valid range depends on the $calendar RETURN VALUES
A Julian Day number. SEE ALSO
cal_from_jd(3), frenchtojd(3), gregoriantojd(3), jewishtojd(3), juliantojd(3), unixtojd(3). PHP Documentation Group CAL_TO_JD(3)
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