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Top Forums UNIX for Dummies Questions & Answers create PATH from find command output Post 302180799 by rein on Tuesday 1st of April 2008 07:24:15 AM
Old 04-01-2008
PATH=$PATH:`find $dir -name "*.jar" | sed 's/$/:/' | xargs`

works but now the output looks like this:

PATH=/path/to/1.jar: /path/to/2.jar: /path/to/3.jar:

with spaces in between, I do the following and that works:

| sed 's/ *//g'`

so the full command is:

Code:
PATH=$PATH:`find $dir -name "*.jar" | sed 's/$/:/' | xargs | sed 's/ *//g'`

 

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BUILD-JAR-REPOSITORY(1) 					   User Commands					   BUILD-JAR-REPOSITORY(1)

NAME
build-jar-repository - create a symbolic link to a JAR SYNOPSIS
build-jar-repository [OPTION]... DIRECTORY... JAR DESCRIPTION
Build a JAR repository in the named directory by copying files or creating symbolic links OPTIONS
If no option is specified the default action will be to create symbolic links -c, --copy copy files -h, --hard create hard links -p, --preserve-naming try to preserve the names of the original JAR files (in case of a nested hit the slashes in the path will still be replaced by underscores) using this option makes any future automated repository rebuild impossible, and implies -c unless specified otherwise -s, --soft, --symbolic create symbolic links (default) --help display help text EXAMPLES
build-jar-repository . jndi will create a symbolic link to the JNDI JAR in the current working directory build-jar-repository -h /tmp oro will create a hard link to the ORO JAR in /tmp AUTHOR
Written by Nicholas Mailhot and David Walluck REPORTING BUGS
Report bugs using JPackage Bugzilla (http://www.jpackage.org/bugzilla/) build-jar-repository (jpackage-utils) 1.7.0 March 2006 BUILD-JAR-REPOSITORY(1)
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