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Full Discussion: Replacing $ in variable
Top Forums UNIX for Dummies Questions & Answers Replacing $ in variable Post 302171699 by sank on Friday 29th of February 2008 08:08:14 AM
Old 02-29-2008
Quote:
Originally Posted by ashish_uiit
yes i see ...expanded variables when i do "echo $k".
To escape $ first i need to replace "$" with "\$".. thats the problem I am facing.
ok. you can turn off variable expansion by having the string in single quotes:
k='$a$b'
echo $k --> returns $a$b
please try to form the string as above.
 

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IS_FLOAT(3)								 1							       IS_FLOAT(3)

is_float - Finds whether the type of a variable is float

SYNOPSIS
bool is_float (mixed $var) DESCRIPTION
Finds whether the type of the given variable is float. Note To test if a variable is a number or a numeric string (such as form input, which is always a string), you must use is_numeric(3). PARAMETERS
o $var - The variable being evaluated. RETURN VALUES
Returns TRUE if $var is a float, FALSE otherwise. EXAMPLES
Example #1 is_float(3) example <?php if (is_float(27.25)) { echo "is float "; } else { echo "is not float "; } var_dump(is_float('abc')); var_dump(is_float(23)); var_dump(is_float(23.5)); var_dump(is_float(1e7)); //Scientific Notation var_dump(is_float(true)); ?> The above example will output: is float bool(false) bool(false) bool(true) bool(true) bool(false) SEE ALSO
is_bool(3), is_int(3), is_numeric(3), is_string(3), is_array(3), is_object(3). PHP Documentation Group IS_FLOAT(3)
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