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Top Forums Programming Using write() with integers in C Post 302166289 by pflynn on Monday 11th of February 2008 01:46:39 PM
Old 02-11-2008
Quote:
Originally Posted by h@run
also: using itoa() produces a " warning: implicit declaration of function 'itoa' " even though i have #included stdlib.h
This is because itoa is not an ANSI C function (though its converse function, atoi, does) so its prototype is not in the stdlib.h header file as you would expect. Probably it is even not supported by your environment. jim mcnamara showed us the portable way one can format an integer into a string using the ANSI sprintf function (check also its secure version, snprintf).
 

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A64L(3) 						     Linux Programmer's Manual							   A64L(3)

NAME
a64l, l64a - convert between long and base-64 SYNOPSIS
#include <stdlib.h> long a64l(char *str64); char *l64a(long value); DESCRIPTION
These functions provide a conversion between 32-bit long integers and little-endian base-64 ASCII strings (of length zero to six). If the string used as argument for a64l() has length greater than six, only the first six bytes are used. If longs have more than 32 bits, then l64a() uses only the low order 32 bits of value, and a64l() sign-extends its 32-bit result. The 64 digits in the base 64 system are: '.' represents a 0 '/' represents a 1 0-9 represent 2-11 A-Z represent 12-37 a-z represent 38-63 So 123 = 59*64^0 + 1*64^1 = "v/". NOTES
The value returned by a64l() may be a pointer to a static buffer, possibly overwritten by later calls. The behaviour of l64a() is undefined when value is negative. If value is zero, it returns an empty string. These functions are broken in glibc before 2.2.5 (puts most significant digit first). CONFORMING TO
XPG 4.2, POSIX 1003.1-2001. SEE ALSO
uuencode(1), itoa(3), strtoul(3) 2002-02-15 A64L(3)
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