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Shell Programming and Scripting

integers in the if statement

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# 1  
Old 01-22-2008
integers in the if statement
hi, im trying to compare two variables in csh to put in an if statement, eg:

set a = $firstnum
set b = $secondnum
if ($a -ge $b) echo $a

But I get an error ("if: Expression syntax"). How can I make csh see my variables as integers?

thanks in advance!
# 2  
Old 01-22-2008
Your code have the syntactical errors

if [ $a -ge $b ]
then
echo $a
fi


Enjoy....
Anji
# 3  
Old 01-22-2008
Quote:
Originally Posted by Anji
Your code have the syntactical errors

if [ $a -ge $b ]
then
echo $a
fi


Enjoy....
Anji
im using csh, this has always been the form of if that i have been using...
# 4  
Old 01-22-2008
You should use greater than symbol
Quote:
Originally Posted by Deanne
hi, im trying to compare two variables in csh to put in an if statement, eg:

set a = $firstnum
set b = $secondnum
if ($a -ge $b) echo $a

But I get an error ("if: Expression syntax"). How can I make csh see my variables as integers?

thanks in advance!
if ($a > $b) echo $a
# 5  
Old 01-22-2008
thanks ranjithpr! it works. it was my first instinct to do that but the "-gt" was what the man pages indicate. i should have tried that one.
Smilie
# 6  
Old 01-22-2008
if ( $a -ge $b) then
echo $a
endif
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