Dear all
I am bit new to programming. I have to redirect the output to a file which will be in the following format
man ls> date +"hup-%m%d%y-%H%M" --------> this will show me the month,day,year,hours and minute in a file name whose name start from "hup-"
kindly any correct my syntax (2 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hii.. Everyone :
I have 15 Sun Servers with Solaris-10, Now on some of the servers when
I execuit the command "date" I get following o/p :
# date
Wed Sep 10 22:29:37 IST 2008
And on some of Servers I am getting :
# date
Wednesday, September 10, 2008 10:23:47 PM IST
Kindly see... (3 Replies)
Hi
I have one problem with cron job in Control Panel.
I have a log file that is created once a day on another server and I need to transfer it in an exact time to my server so I wrote the cron job for it BUT the problem is in the date command:
/filelog-`date +%Y-%m-%d`.tar.gz;
The file... (1 Reply)
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
Hello,
Can anyone have an idea what is wrong with this code:
$ YESTERDAY=$(date -d "yesterday" '+%Y-%m-%d 07:00:00')
$ echo $YESTERDAY
2016-12-26 07:00:00
$ date -d '($YESTERDAY)' +"%s000"
1482793200000
1482793200000 is not correct, it should be: 1482732000000
Result when... (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT OPENSOLARIS
sulog
sulog(4) File Formats sulog(4)NAME
sulog - su command log file
SYNOPSIS
/var/adm/sulog
DESCRIPTION
The sulog file is a record of all attempts by users on the system to execute the su(1M) command. Each time su(1M) is executed, an entry
is added to the sulog file.
Each entry in the sulog file is a single line of the form:
SU date time
result port user-newuser
where
date The month and date su(1M) was executed. date is displayed in the form mm/dd where mm is the month number and dd is the day
number in the month.
time The time su(1M) was executed. time is displayed in the form HH/MM where HH is the hour number (24 hour system) and MM is the
minute number.
result The result of the su(1M) command. A ` + ' sign is displayed in this field if the su attempt was successful; otherwise a ` - '
sign is displayed.
port The name of the terminal device from which su(1M) was executed.
user The user id of the user executing the su(1M) command.
newuser The user id being switched to with su(1M).
EXAMPLES
Example 1 A sample sulog file.
Here is a sample sulog file:
SU 02/25 09:29 + console root-sys
SU 02/25 09:32 + pts/3 user1-root
SU 03/02 08:03 + pts/5 user1-root
SU 03/03 08:19 + pts/5 user1-root
SU 03/09 14:24 - pts/5 guest3-root
SU 03/09 14:24 - pts/5 guest3-root
SU 03/14 08:31 + pts/4 user1-root
FILES
/var/adm/sulog su log file
/etc/default/su contains the default location of sulog
SEE ALSO su(1M)SunOS 5.11 6 Jun 1994 sulog(4)