01-16-2008
This command prints only one single space between each arguments.Not all the spaces!!!
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1. Shell Programming and Scripting
I want to be able to read in input which contain spaces and put that into an array. Each field should be delimeted by a space and should be a different array element. However I cant get it to work. any tips?
read input
//type field1 field2 field3
echo "$input"
array="$input"
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2. Shell Programming and Scripting
Hello all,
I want to list the file contents of the directory and number them. I am using la and awk to do it now,
#ls |awk '{print NR "." $1}'
1. alpha
2. beta
3. gamma
The problem I have is that some files might also have some spaces in the filenames.
#ls
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3. Shell Programming and Scripting
Let's say I want to print the arguments $4 till $#, how can I do this?
$# contains the number of arguments
$@ contain all the arguments as string
What i need is something like
for i in $4_till_$#; do
#do something with $i
convert $i ~/$output
done
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When I use:
find . -ls | awk 'BEGIN { OFS = ";"} {print $1,$2,$11}'I get a nice result, yet the files with spaces in it show only the first word and all other characters after the blank space are not printed.
e.g. 'file with a blank space'
is printed
file
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Hey all,
How do I make a script print its arguments in reverse order?
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6. Shell Programming and Scripting
Hi All,
I want to pass few dynamic arguments to shell script. The number of arguments differ each time I call the script.
I want to print the arguments using the for loop as below. But not working out.
for (( i=1; i<=$#; i++ ))
do
echo $"($i)"
done
/bin/sh test.sh arg1 arg2 arg3
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I have simple test.sh script, see below:
bill_code=`echo $record | awk -F"|" '{print $1}'`
Fullname=`echo $record | awk -F"|" '{print $3}'`
email=`echo $record | awk -F\ '{print $4}'`
The last field contains spaces: see csv below:
A0222|Y|DELACRUZ|-cc dell@yahoo.com-cc support@yahoo.com
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Hi,
I'm using awk to print columns from a tab delimited text file:
awk '{print " "$2" "$3" $6"}' file
The problem I have is column 6 contains text with spaces etc which means awk only prints the first word.
How can I tell awk to print the whole column content as column 6?
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Hi all,
I want to set 10 set of strings into a variable where:
removing all spaces within each string
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LEARN ABOUT DEBIAN
concat
concat(3tcl) Tcl Built-In Commands concat(3tcl)
__________________________________________________________________________________________________________________________________________________
NAME
concat - Join lists together
SYNOPSIS
concat ?arg arg ...?
_________________________________________________________________
DESCRIPTION
This command joins each of its arguments together with spaces after trimming leading and trailing white-space from each of them. If all
the arguments are lists, this has the same effect as concatenating them into a single list. It permits any number of arguments; if no args
are supplied, the result is an empty string.
EXAMPLES
Although concat will concatenate lists, flattening them in the process (so giving the following interactive session):
% concat a b {c d e} {f {g h}}
a b c d e f {g h}
it will also concatenate things that are not lists, as can be seen from this session:
% concat " a b {c " d " e} f"
a b {c d e} f
Note also that the concatenation does not remove spaces from the middle of values, as can be seen here:
% concat "a b c" { d e f }
a b c d e f
(i.e., there are three spaces between each of the a, the b and the c).
SEE ALSO
append(3tcl), eval(3tcl), join(3tcl)
KEYWORDS
concatenate, join, lists
Tcl 8.3 concat(3tcl)