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Top Forums Shell Programming and Scripting Compare two arrays in sh or compare two fields Post 302143191 by rijeshpp on Wednesday 31st of October 2007 02:47:02 AM
Old 10-31-2007
Compare two arrays in sh or compare two fields

I want a soultion to compare two arrays in sh with an easy way.I want a solution to synchrose users between different AIX servers where no NIS is available. All users are meant to be same on all 10 servers. So the approach is to consider first server as master user repository and whatever the users are created on it has to extract in a format and use a tempate file for creating missing users on other servers by comparing values in template file with its /etc/passwd file.

Hence my template file creates on following command

`cat /etc/passwd | awk -F ':' '{printf("%-15s %-62s %-5s %-5s \n",$1,$5,$4,$6)}'` > allusers.txt

Which will have all the fields to create users.At the same time i need to remove the service accounts like root dameon etc from allusers.txt. So service accounts are already known and assigned into an variable.

SERVICE_ACCOUNTS="root daemon bin sys adm uucp nobody lpd lp invscout snapp ipsec nuucp sshd wasadmin db2inst1 dasusr1 db2fenc1 db2inst2 db2fenc2 vobadm gpausr"


Need to extract userlogin from allusers.txt by comparing SERVICE_ACCOUNTS.

createProjectUserTemplate()
{

#Find all users, Construct list and then compare with defined service account users list
`cat /etc/passwd | awk -F ':' '{printf("%-15s %-62s %-5s %-5s \n",$1,$5,$4,$6)}'` > allusers.txt
set -A serviceAccountsList $SERVICE_ACCOUNTS
#Construct user login from allusers
allUserLogins=`cut -f1 -d ' ' allusers.txt`
set -A totUserLoginsList $totUserLogins
#Differentiate two lists and find and construct Project user list and put into ProjectUserTemplate.txt file along with rest of the field
Need s suitable easy way of comaparing.
}

Can anyone help me to compare these values in an easy way as i am new to shell scripting. All i know is that we have to use sh or ksh becasue bash is not install on AIX by default.

I have seen another question almost similar to me on the link
Comparing Arrays? . But the solution given there is not working me when i cut userlogin field and then assigning to variable.

i.e. the problem in tha tway is

a1="root daemon bin sys adm uucp nobody lpd lp invscout snapp ipsec nuucp sshd wasadmin db2inst1 dasusr1 db2fenc1 db2inst2 db2fenc2 vobadm gpausr"
a2=`cut -f1 -d ' ' allusers.txt`

Then

a3=$(printf "$a1\n$a2"|awk '{for(i=1;i<=NF;i++)if(NR==1)a[$i]=i;else if(!($i in a))print $i}')

does not give me the difference as seems to be problem with cut. If there is a solution to this then aslo i will be grateful.

Thanks in advance,
Rijesh.
 

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d_passwd(4)							   File Formats 						       d_passwd(4)

NAME
d_passwd - dial-up password file SYNOPSIS
/etc/d_passwd DESCRIPTION
A dial-up password is an additional password required of users who access the computer through a modem or dial-up port. The correct pass- word must be entered before the user is granted access to the computer. d_passwd is an ASCII file which contains a list of executable programs (typically shells) that require a dial-up password and the associ- ated encrypted passwords. When a user attempts to log in on any of the ports listed in the dialups file (see dialups(4)), the login program looks at the user's login entry stored in the passwd file (see passwd(4)), and compares the login shell field to the entries in d_passwd. These entries determine whether the user will be required to supply a dial-up password. Each entry in d_passwd is a single line of the form: login-shell:password: where login-shell The name of the login program that will require an additional dial-up password. password An encrypted password. Users accessing the computer through a dial-up port or modem using login-shell will be required to enter this password before gaining access to the computer. d_passwd should be owned by the root user and the root group. The file should have read and write permissions for the owner (root) only. If the user's login program in the passwd file is not found in d_passwd or if the login shell field in passwd is empty, the user must sup- ply the default password. The default password is the entry for /usr/bin/sh. If d_passwd has no entry for /usr/bin/sh, then those users whose login shell field in passwd is empty or does not match any entry in d_passwd will not be prompted for a dial-up password. Dial-up logins are disabled if d_passwd has only the following entry: /usr/bin/sh:*: EXAMPLES
Example 1: Sample d_passwd file. Here is a sample d_passwd file: /usr/lib/uucp/uucico:q.mJzTnu8icF0: /usr/bin/csh:6k/7KCFRPNVXg: /usr/bin/ksh:9df/FDf.4jkRt: /usr/bin/sh:41FuGVzGcDJlw: Generating An Encrypted Password The passwd (see passwd(1)) utility can be used to generate the encrypted password for each login program. passwd generates encrypted pass- words for users and places the password in the shadow (see shadow(4)) file. Passwords for the d_passwd file will need to be generated by first adding a temporary user id using useradd (see useradd(1M)), and then using passwd(1) to generate the desired password in the shadow file. Once the encrypted version of the password has been created, it can be copied to the d_passwd file. For example: 1. Type useradd tempuser and press Return. This creates a user named tempuser. 2. Type passwd tempuser and press Return. This creates an encrypted password for tempuser and places it in the shadow file. 3. Find the entry for tempuser in the shadow file and copy the encrypted password to the desired entry in the d_passwd file. 4. Type userdel tempuser and press Return to delete tempuser. These steps must be executed as the root user. FILES
/etc/d_passwd dial-up password file /etc/dialups list of dial-up ports requiring dial-up passwords /etc/passwd password file /etc/shadow shadow password file SEE ALSO
passwd(1), useradd(1M), dialups(4), passwd(4), shadow(4) WARNINGS
When creating a new dial-up password, be sure to remain logged in on at least one terminal while testing the new password. This ensures that there is an available terminal from which you can correct any mistakes that were made when the new password was added. SunOS 5.10 2 Sep 2004 d_passwd(4)
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