I have an input below. I tried to use the awk below but it seems that it ;s not working. Can anybody help ?
My concept here is to find the 2nd field of the last occurrence of such pattern " ** XXX ccc ccc cc cc ccc 2007 " . In this case, the 2nd field is " XXX ". With this "XXX" term stored as a variable, i want to print out the all lines with 2nd field having " XXX " term and its subsequent lines containing terms matching with " k= ". Expected output are highlighted as bold red in the input.
Input:
wwwwww
0999 k= 1
wwwwww ** XXX ccc ccc cc cc ccc 2007
wwwwww
wwwwww 0001 k= 1
wwwwww 0002 k= 1
** abc ccc cc cc cc cc 2007
wwwwww
0001 k= 1
wwwwww
0002 k= 1
wwwwww
wwwwww
0003 k= 1
wwwwww ** XXX ccc ccc cc cc ccc 2007
wwwwww 0003 k= 1
wwwwww 0004 k= 1 0005 k= 1
Output:
** XXX ccc ccc cc cc ccc 2007
0001 k= 1
0002 k= 1
** XXX ccc ccc cc cc ccc 2007
0003 k= 1
0004 k= 1
0005 k= 1
i have an awk statement which i am using to count the number of occurences of the number ,5, in the file:
awk '/,5,/ {count++}' TRY.txt | awk 'END { printf(" Total parts: %d",count)}'
i know there is a total of 10 matches..what is wrong here?
thanks (16 Replies)
Hi
I have files with names that contain the date in several formats as, YYYYMMDD, DD-MM-YY,DD.MM.YY or similar combinations.
I know if a file fits in one pattern or other, but i donīt know how to extract the substring contained in the file that matches the pattern.
For example, i know that
... (1 Reply)
but keep if does not
I have a file: --> my.out
foo: bar
foo: moo
blarg
i am on vacation
foo: goose
foo: lucy
foo: moose
foo: stucky
groover@monkey.org
foo: bozo
grimace@gonzo.net
dear sir - blargo blargo
foo: goon
foo: sloppy
foo: saudi
gimme gimme gimme (3 Replies)
Hi,
I'm having trouble pulling out columns where the headers match a file of key ID's I'm interested in and was looking for some help.
file1.txt
I
Name
34
56
84
350
790
1215
1919
7606
9420
file2.txt
I Name 1 1 2 2 3 3 ... 34 34... 56 56... 84 84... 350 350...
M 1 A A A A... (20 Replies)
To match range, the command is:
awk '/BEGIN/,/END/'
but what I want is the range is printed only if there is additional pattern that matches in the range itself? maybe like this:
awk '/BEGIN/,/END/ if only in that range there is /pattern/'
Thanks (8 Replies)
I sat down yesterday to write this script and have just realised that my methodology is broken........
In essense I have.....
----------------------------------------------------------------- (This line really is in the file)
Service ID: 12345 ... (7 Replies)
Hi
I have a big text file. I want to extract all the sentences that matches at least 70% (seventy percent) of the words from each sentence based on a word list called A.
Say the format of the text file is as given below:
This is the first sentence which consists of fifteen words... (4 Replies)
Hi Guys,
How to achieve this in awk or sed:
Patterns: A.B. No. T-8346 or A.B. No. T-8xxx
will look like this:
Patterns: A.B. No. T-8346<br> or A.B. No. T-8xxx<br>
#cat file.txt
JHON VS. PETER, AGOO PET.
How Old Are Youthe file will look like this:
A.B. No. T-8346<br> January 01,... (10 Replies)
Hi all,
I have file on which I do grep on "/tmp/data" then I get 5 lines as
dir Path: /tmp/data/20162343134
Starting to listen on ports logging:
--
Moving results files from local storage: /tmp/resultsFiles/20162343134/*.gz to NFS: /data/temp/20162343134/outgoing
from above got to get... (7 Replies)
Hi,
I have to extract the whole set if a pattern matches.i have a file called input.txt
input.txt
------------
CREATE TABLE ABC
(
A,
B,
C
);
CREATE TABLE XYZ
(
X,
Y,
Z,
P,
Q
); (6 Replies)
Discussion started by: raju2016
6 Replies
LEARN ABOUT DEBIAN
z88dk-copt
copt(1) z88 Development Kit copt(1)NAME
copt - peephole optimizer
SYSNOPIS
copt file ...
DESCRIPTION
copt is a general-purpose peephole optimizer. It reads code from its standard input and writes an improved version to its standard output.
copy reads the named files for its optimizations, which are encoded as follows:
<pattern for input line 1>
<pattern for input line 2>
...
<pattern for input line n>
=
<pattern for output line 1>
<pattern for output line 2>
...
<pattern for output line m>
<blank line>
Pattern matching uses literal string comparison, with one exception: ``%%'' matches the ``%'' character, and ``%'' followed by a digit
matches everything up to the next occurrence of the next pattern character, though all occurrences of %n must denote the same string. For
example, the pattern ``%1=%1.'' matches exactly those strings that begin with a string X, followed by a ``='' (the first), followed by a
second occurrence of X, followed by a period. In this way, the input/output pattern
mov $%1,r%2
mov *r%2,r%2
=
mov %1,r%2
commands copt to replace runs like
mov $_a,r3
mov *r3,r3
with
mov _a,r3
Note that a tab or newline can terminate a %n variable.
copt compares each run of input patterns with the current input instruction and its predecessors. If no match is found, it advances to the
next input instruction and tries again. Otherwise, it replaces the input instructions with the corresponding output patterns, pattern vari-
ables instantiated,and resumes its search with the first instruction of the replacement. copt matches input patterns in reverse order to
cascade optimizations without backing up.
BUGS
Errors in optimization files are always possible.
SEE ALSO z88dk(1), z88dk-zcc(1), z88dk-z80asm(1), z88dk-appmake(1), z88dk-copt(1).
AUTHOR
z88dk was written by Dominic Morris <dom@z88dk.org>, and others.
01 December 2009 copt(1)