10-04-2007
awk + last occurrence
Hi,
I'm attempting to search, using awk, a pattern range in a file. Something like:
>awk '/first bit of text.../,/...last bit of text/' file
Is it possible to print only the last (or first) occurrence of the pattern range this way?
Thanks for any suggestions.
Al
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LEARN ABOUT DEBIAN
regexp
Regexp(3I) InterViews Reference Manual Regexp(3I)
NAME
Regexp - regular expression searching
SYNOPSIS
#include <InterViews/regexp.h>
DESCRIPTION
A Regexp encapsulates a regular expression pattern and defines operations for searching and matching the pattern against a string. The
syntax of the regular expression pattern is the same as that for ed(1). Information can be obtained about the most recent match of the
regular expression (and its sub-expressions).
PUBLIC OPERATIONS
Regexp(const char* pattern)
Regexp(const char* pattern, int length)
Construct a new Regexp for pattern.
int Match(const char* text, int length, int index)
Attempt a match against text (of length length) at position index. The return value is the length of the matching string, or a neg-
ative number if the match failed.
int Search(const char* text, int length, int index, int range)
Search for a match in the string text (of length length). Matches are attempted starting at positions between index and index plus
range. If range is positive the first match after index is reported. If range is negative the first match before index is
reported. The return value is the index of the starting position of the match, or a negative number if there is no match in the
specified range.
int BeginningOfMatch(int subexp)
int EndOfMatch(int subexp)
Return information about the most recent match. If subexp is zero (the default), information is reported for the complete regular
expression. Other values of subexp refer to sub-expressions in the pattern. For example, if subexp is 2, information is returned
for the sub-expression specified by the second pair of ( and ) delimiters in the pattern.
SEE ALSO
ed(1)
InterViews 23 May 1989 Regexp(3I)