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Top Forums Shell Programming and Scripting replace first character of string sed Post 302130156 by prkfriryce on Friday 3rd of August 2007 09:20:16 AM
Old 08-03-2007
Quote:
Originally Posted by lorcan
Finally i could get only this

Code:
echo $(echo test | cut -c1 | tr '[a-z]' '[A-Z]')$(echo test | cut -c2-)

Might be others have different ideas...
thanks, just tried an awk example that works for the first character as well

Code:
bash-2.03$ echo test |awk '
BEGIN { upper = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
lower = "abcdefghijklmnopqrstuvwxyz"
}
{
FIRSTCHAR = substr($1, 1, 1)
if (CHAR = index(lower, FIRSTCHAR))
$1 = substr(upper, CHAR, 1) substr($1, 2)
print $0
}'
Test

 

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BASENAME(3)								 1							       BASENAME(3)

basename - Returns trailing name component of path

SYNOPSIS
string basename (string $path, [string $suffix]) DESCRIPTION
Given a string containing the path to a file or directory, this function will return the trailing name component. PARAMETERS
o $path - A path. On Windows, both slash ( /) and backslash ( ) are used as directory separator character. In other environments, it is the forward slash ( /). o $suffix - If the name component ends in $suffix this will also be cut off. RETURN VALUES
Returns the base name of the given $path. EXAMPLES
Example #1 basename(3) example <?php echo "1) ".basename("/etc/sudoers.d", ".d").PHP_EOL; echo "2) ".basename("/etc/sudoers.d").PHP_EOL; echo "3) ".basename("/etc/passwd").PHP_EOL; echo "4) ".basename("/etc/").PHP_EOL; echo "5) ".basename(".").PHP_EOL; echo "6) ".basename("/"); ?> The above example will output: 1) sudoers 2) sudoers.d 3) passwd 4) etc 5) . 6) NOTES
Note basename(3) operates naively on the input string, and is not aware of the actual filesystem, or path components such as " ..". Note basename(3) is locale aware, so for it to see the correct basename with multibyte character paths, the matching locale must be set using the setlocale(3) function. SEE ALSO
dirname(3), pathinfo(3). PHP Documentation Group BASENAME(3)
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