QUESTION: How can I cut out the date from just the first line and reformat it to 31-Jul-2007? I'll restate the question at the bottom again...
DESCRIPTION: I need to cut a date out of a file - an example of the date's format in the file is 2007-07-31. It's in the 5th field and is separated... (1 Reply)
Hi All,
How can i use the cut option to only output the number of rows, which is 2 is this case ? Pls note that the number of digit before the delimiter ":" is always varying.
$ grep -n uuu xxx
2:** xxx yyy gg 44 tt uuu 2007
$ (2 Replies)
Is there a way to use a word as a delimiter with cut? Or is there a way to use sed or awk with a word as a delimiter? I don't care which program I use for a delimiter I just want to use a word as a delimiter. (2 Replies)
I need to cut or otherwise get the 4th and 5th position output of
for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done
example output is:
h;13;1310318701;443;93
I only need ";443;93" from any given run of "for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done"
Thanks... (3 Replies)
HI,
I have a file like below
"103865","103835","Zming","","Zhu","103965","Sunnyvale","US",
"116228","116227","Morlla","","Kowalski","113228","Paese "(Treviso)""IT"
I want to validate the 7th column which is below.
"Sunnyvale"
"Paese
In the above 7th column Paese is not ended with... (9 Replies)
hi all,
suppose a string:
abc/def/ghi/jkl/mn.txt
and i want to get the file name without the path.
however, different files have different paths, therefore the number of delimiter is uncertain.
thanks so much! (3 Replies)
Hi all,
I have a number of strings like below:
//mnt/autocor/43°13'(33")W/
and i'm trying to get the numbers in this string, for example
431333
please help
thanks ahead (14 Replies)
Hi,
Can someone help me to get the shortest command
Input file
=========
I|know|"english|french"
It|can|have|four|delimiters
Desired output
===========
"english|french"
have
If I use cut -d "|" -f3 , i am getting "english as 3rd field.But I would like to get the whole text in... (2 Replies)
i have list of names in a text file and I wanted to delete the commas en every line.
for example: inside the text is a list of names in it with commas after each line. I wanted to delete these commas. which command must I execute for this?
unix,
dale,
shawn,
aaron, (4 Replies)
Hi All-
We have a file data as below with delimiter as |#|
10|#|20|#|ABC
13|#|23|#|PBC
If I want to cut the 2nd field out of this, below command is not working as multiple pipe is causing an issue , it seems
cut -f2 -d"|#|" <file_name>
can you please help to provide the correct command... (7 Replies)
Discussion started by: sureshg_sampat
7 Replies
LEARN ABOUT OSX
cut
CUT(1) BSD General Commands Manual CUT(1)NAME
cut -- cut out selected portions of each line of a file
SYNOPSIS
cut -b list [-n] [file ...]
cut -c list [file ...]
cut -f list [-d delim] [-s] [file ...]
DESCRIPTION
The cut utility cuts out selected portions of each line (as specified by list) from each file and writes them to the standard output. If no
file arguments are specified, or a file argument is a single dash ('-'), cut reads from the standard input. The items specified by list can
be in terms of column position or in terms of fields delimited by a special character. Column numbering starts from 1.
The list option argument is a comma or whitespace separated set of numbers and/or number ranges. Number ranges consist of a number, a dash
('-'), and a second number and select the fields or columns from the first number to the second, inclusive. Numbers or number ranges may be
preceded by a dash, which selects all fields or columns from 1 to the last number. Numbers or number ranges may be followed by a dash, which
selects all fields or columns from the last number to the end of the line. Numbers and number ranges may be repeated, overlapping, and in
any order. If a field or column is specified multiple times, it will appear only once in the output. It is not an error to select fields or
columns not present in the input line.
The options are as follows:
-b list
The list specifies byte positions.
-c list
The list specifies character positions.
-d delim
Use delim as the field delimiter character instead of the tab character.
-f list
The list specifies fields, separated in the input by the field delimiter character (see the -d option.) Output fields are separated
by a single occurrence of the field delimiter character.
-n Do not split multi-byte characters. Characters will only be output if at least one byte is selected, and, after a prefix of zero or
more unselected bytes, the rest of the bytes that form the character are selected.
-s Suppress lines with no field delimiter characters. Unless specified, lines with no delimiters are passed through unmodified.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of cut as described in environ(7).
EXIT STATUS
The cut utility exits 0 on success, and >0 if an error occurs.
EXAMPLES
Extract users' login names and shells from the system passwd(5) file as ``name:shell'' pairs:
cut -d : -f 1,7 /etc/passwd
Show the names and login times of the currently logged in users:
who | cut -c 1-16,26-38
SEE ALSO colrm(1), paste(1)STANDARDS
The cut utility conforms to IEEE Std 1003.2-1992 (``POSIX.2'').
HISTORY
A cut command appeared in AT&T System III UNIX.
BSD December 21, 2006 BSD