05-31-2007
sed question please help
I have many of this similar lines in a file and it is always start with number 7. How can replace this Whole-Line with something that I want.
7 ;0;12 ;3;0; ; ; ;ABCD ;n;n; ; ; ; ; ;
I tried:
sed 's/^7/tom/g' file
I get:
tom ;0;12 ;3;0; ; ; ;ABCD ;n;n; ; ; ; ; ;
Also,
there are lines that may start with 70, 71,.....79. How can I make it works for just "7"
For example:
79 ;0;12 ;3;0; ; ; ;ABCD ;n;n; ; ; ; ; ;
I will get:
tom9 ;0;12 ;3;0; ; ; ;ABCD ;n;n; ; ; ; ; ;
Many Thanks!
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LEARN ABOUT OSX
digest::crc
Digest::CRC(3) User Contributed Perl Documentation Digest::CRC(3)
NAME
Digest::CRC - Generic CRC functions
SYNOPSIS
# Functional style
use Digest::CRC qw(crc64 crc32 crc16 crcccitt crc crc8 crcopenpgparmor);
$crc = crc64("123456789");
$crc = crc32("123456789");
$crc = crc16("123456789");
$crc = crcccitt("123456789");
$crc = crc8("123456789");
$crc = crcopenpgparmor("123456789");
$crc = crc($input,$width,$init,$xorout,$refout,$poly,$refin,$cont);
# add data to existing
$crc = crc32("ABCD", $crc);
# OO style
use Digest::CRC;
$ctx = Digest::CRC->new(type=>"crc16");
$ctx = Digest::CRC->new(width=>16, init=>0x2345, xorout=>0x0000,
refout=>1, poly=>0x8005, refin=>1, cont=>1);
$ctx->add($data);
$ctx->addfile(*FILE);
$digest = $ctx->digest;
$digest = $ctx->hexdigest;
$digest = $ctx->b64digest;
DESCRIPTION
The Digest::CRC module calculates CRC sums of all sorts. It contains wrapper functions with the correct parameters for CRC-CCITT, CRC-16,
CRC-32 and CRC-64, as well as the CRC used in OpenPGP's ASCII-armored checksum.
SEE ALSO
https://tools.ietf.org/html/rfc4880#section-6
AUTHOR
Oliver Maul, oli@42.nu
COPYRIGHT
CRC algorithm code taken from "A PAINLESS GUIDE TO CRC ERROR DETECTION
ALGORITHMS".
The author of this package disclaims all copyrights and releases it into the public domain.
perl v5.16.2 2013-08-25 Digest::CRC(3)