Hi,
using awk /sed, I need to sort out the input file.
here is the example
input file===
Name= shashi | country= india | region = asia | dept= ww
Name= jon | region = asia | dept= xx
Name=sam | dept= ww
Name= anthony | country=england | dept= xx
Name= sumo | country= china
output... (3 Replies)
Hi Friends,
Scripting newb here. So I'm trying to create a geektool script that uses awk and printf to output certain fields from top (namely command, cpu%, rsize, pid and time, in that order). After much trial and error, I've pretty much succeeded, with one exception. Any process whose name... (3 Replies)
Target file contains short text (never more than 1 line) and filenames.
The format is, e.g.,:
TEXT1
filename1
TEXT2
TEXT3
filename3dddd
filename3dddd
TEXT4
filename4
TEXT5
filename5dddd
filename5dddd
filename5
where dddd is a random 4-digit whole number.
Desired output: (4 Replies)
Hi,
I have the following text file:
8 T1mapping_flip02 ok 128 108 30 1 665000-000008-000001.dcm
9 T1mapping_flip05 ok 128 108 30 1 665000-000009-000001.dcm
10 T1mapping_flip10 ok 128 108 30 1 665000-000010-000001.dcm
11 T1mapping_flip15 ok 128 108 30... (2 Replies)
Hi,
I am using the following code to assign a count value to a variable. But I get nothing. Do you see anything wrong here.
I am new to all this.
$CTR=`remsh $m -l $MACHINES{$m} -n cat $output | grep -v sent | grep \"$input\" | sort -u | awk '{print $5}'`;
Upto sort - u it's... (2 Replies)
Hi All, Need Suggestion, Want to sort a file using awk & sed to get required, output as below, such that each LUN shows correct WWPN and FA port Numbers correctly:
Required output:
01FB 10000000c97843a2 8C 0
01FB 10000000c96fb279 9C 0
22AF 10000000c97843a2 8C 0
22AF 10000000c975adbd ... (10 Replies)
I have a problem with my homework I need to create a shell script using #!bin/awk -f
the script will output the file in an alphabetical order only words and after the word is : after that a space then , then it will be numbered each character by which line its been for example
CB
92A
A... (1 Reply)
I have file and process it and provide clean output.
input file
Device Symmetrix Name : 000A4
Device Symmetrix Name : 000A5
Device Symmetrix Name : 000A6
Device Symmetrix Name : 000A7
Device Symmetrix Name : 000A8
Device Symmetrix Name : 000A9
Device Symmetrix Name ... (10 Replies)
Discussion started by: ranjancom2000
10 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)