|
|
Sponsored Content
Top Forums
UNIX for Dummies Questions & Answers
date format
Post 302096598 by vino on Thursday 16th of November 2006 01:44:19 PM
|
|
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
hi,
for reading a cobol indexed file i need to convert "mmddyy" date format to "ccyyddd" format.
i checked the datecalc and other scripts but couldnt modify them to cater to my need:(...
The datecalc gives an output which i believe is the total days till that date, but i want to convert it... (2 Replies)
Discussion started by: Bhups
2 Replies
2. UNIX for Advanced & Expert Users
Hi ,
I have written a shell script that takes the current date on the server and stores it in a file.
echo get /usr/home/data-`date '+%Y%d'`.xml> /usr/local/sandeep/GetFILE.ini
I call this GetFILE.ini file from an sftp program to fetch a file from /usr/home/ as location. The file is in... (3 Replies)
Discussion started by: bsandeep_80
3 Replies
3. Shell Programming and Scripting
I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column.
I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this?
Sample input
02/27/09,23:52:31
02/27/09,23:52:52... (3 Replies)
Discussion started by: hazno
3 Replies
4. UNIX for Dummies Questions & Answers
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
Discussion started by: figaro
2 Replies
5. Shell Programming and Scripting
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Discussion started by: sunil087
1 Replies
6. Shell Programming and Scripting
Hello Experts,
How do i get date after 5 days from current date in YYYYMMDD format?
How do you compare date in YYYYMMDD format?
Thanks (8 Replies)
Discussion started by: needyourhelp10
8 Replies
7. UNIX for Dummies Questions & Answers
Shell Scripts - shows today’s date and time in a better format than ‘date’ (Uses positional paramete
Hello,
I am trying to show today's date and time in a better format than ‘date' (Using positional parameters). I found a command mktime and am wondering if this is the best command to use or will this also show me the time elapse since 1/30/70? Any help would be greatly appreciated, Thanks... (3 Replies)
Discussion started by: citizencro
3 Replies
8. Shell Programming and Scripting
hi there
I have file names in different format as below
triss_20111117_fxcb.csv
triss_fxcb_20111117.csv
xpnl_hypo_reu_miplvdone_11172011.csv
xpnl_hypo_reu_miplvdone_11-17-2011.csv
xpnl_hypo_reu_miplvdone_20111117.csv
xpnl_hypo_reu_miplvdone_20111117xfb.csv... (10 Replies)
Discussion started by: manas_ranjan
10 Replies
9. UNIX for Dummies Questions & Answers
Hi Unix Gurus,
I would like to rename several files in a Unix Directory . The filenames can have more than 1 underscore ( _ ) and the last underscore is always followed by a date in the format mmddyyyy. The Extension of the files can be .txt or .pdf or .xls etc and is case insensitive ie... (1 Reply)
Discussion started by: pchegoor
1 Replies
10. Shell Programming and Scripting
i try to set linux date & time in specific format but it keep giving me error
Example :
date "+%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01"
or
date +"%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01"
keep giving me this error :
date: invalid date ‘19-01-2017 00:05:01'
Please use CODE tags... (7 Replies)
Discussion started by: umen
7 Replies
LEARN ABOUT OPENSOLARIS
cal
cal(1) User Commands cal(1) NAME
cal - display a calendar SYNOPSIS
cal [ [month] year] DESCRIPTION
The cal utility writes a Gregorian calendar to standard output. If the year operand is specified, a calendar for that year is written. If no operands are specified, a calendar for the current month is written. OPERANDS
The following operands are supported: month Specify the month to be displayed, represented as a decimal integer from 1 (January) to 12 (December). The default is the current month. year Specify the year for which the calendar is displayed, represented as a decimal integer from 1 to 9999. The default is the current year. ENVIRONMENT VARIABLES
See environ(5) for descriptions of the following environment variables that affect the execution of cal: LANG, LC_ALL, LC_CTYPE, LC_TIME, LC_MESSAGES, and NLSPATH. TZ Determine the timezone used to calculate the value of the current month. EXIT STATUS
The following exit values are returned: 0 Successful completion. >0 An error occurred. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWesu | +-----------------------------+-----------------------------+ |Interface Stability |Standard | +-----------------------------+-----------------------------+ SEE ALSO
calendar(1), attributes(5), environ(5), standards(5) NOTES
An unusual calendar is printed for September 1752. That is the month 11 days were skipped to make up for lack of leap year adjustments. To see this calendar, type: cal 9 1752 The command cal 83 refers to the year 83, not 1983. The year is always considered to start in January. SunOS 5.11 1 Feb 1995 cal(1)