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Full Discussion: echo not echoing correctly
Top Forums UNIX for Dummies Questions & Answers echo not echoing correctly Post 302090442 by anbu23 on Monday 25th of September 2006 04:33:57 PM
Old 09-25-2006
try this
Code:
IFS=""
cat f |
while
read rva
do
num=`echo $rva | cut -d" " -f1-2`
reg=`echo $rva | cut -c10`
ocn=`echo $rva | cut -c12-15`
x=`echo $rva | cut -c29`
xx=`echo $rva | cut -c30`
cli=`echo $rva | cut -c17-27`
tec=`echo $rva | cut -c31-33`
# rat=`echo $rva | cut -c41-49`
# rax=`echo $rva | cut -c67-41`
# lat=`echo $rva | cut -c51-53`
print "$num $reg $ocn $x $xx $cli $tec" >> tu
done

 

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BASENAME(3)								 1							       BASENAME(3)

basename - Returns trailing name component of path

SYNOPSIS
string basename (string $path, [string $suffix]) DESCRIPTION
Given a string containing the path to a file or directory, this function will return the trailing name component. PARAMETERS
o $path - A path. On Windows, both slash ( /) and backslash ( ) are used as directory separator character. In other environments, it is the forward slash ( /). o $suffix - If the name component ends in $suffix this will also be cut off. RETURN VALUES
Returns the base name of the given $path. EXAMPLES
Example #1 basename(3) example <?php echo "1) ".basename("/etc/sudoers.d", ".d").PHP_EOL; echo "2) ".basename("/etc/sudoers.d").PHP_EOL; echo "3) ".basename("/etc/passwd").PHP_EOL; echo "4) ".basename("/etc/").PHP_EOL; echo "5) ".basename(".").PHP_EOL; echo "6) ".basename("/"); ?> The above example will output: 1) sudoers 2) sudoers.d 3) passwd 4) etc 5) . 6) NOTES
Note basename(3) operates naively on the input string, and is not aware of the actual filesystem, or path components such as " ..". Note basename(3) is locale aware, so for it to see the correct basename with multibyte character paths, the matching locale must be set using the setlocale(3) function. SEE ALSO
dirname(3), pathinfo(3). PHP Documentation Group BASENAME(3)
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