Hello,
I'm trying to write a method which will return the extension of a file given the file's name, e.g. test.txt should return txt. I'm using C so am limited to char pointers and arrays. Here is the code as I have it:
char* getext(char *file)
{
char *extension;
int i, j;... (5 Replies)
Heeloo all,
A weird problem perhaps. May god save others from this problem.
I want to print each line from a variable.. the example below should make it clear.
smvar="Hello World1
Hello world 2
forgot there I guess"
for eachline in $smvar
echo $eachline
end
Whats for... (3 Replies)
Hello,
Need help substituting a particular word in a file having a single line but no newline character at the end.
I was trying to use sed but it doesn't work probably because there is no newline char at the end of the line.
$ cat hlq_detail
/outputs/alvan23/PDFs/bills
$ cat... (5 Replies)
Compiling xpp (The X Printing Panel) on SL6 (RHEL6 essentially):
xpp.cxx: In constructor ‘printFiles::printFiles(int, char**, int&)’:
xpp.cxx:200: error: invalid conversion from ‘const char*’ to ‘char*’
The same error with all c++ constructors - gcc 4.4.4.
If anyone can throw any light on... (8 Replies)
Greetings!
Can we automate the process of removing a newline char from selected rows in a fixed width file using a shell?
Input is like
abcd1234
xyzd1234
abcd
a1b2c3d4
abcd1234
xyzd1234
xx
abcd1234
Expected output -
abcd1234xyzd1234
abcda1b2c3d4abcd1234xyzd1234
xxabcd1234
... (2 Replies)
Greetings!
Can we automate the process of removing a newline char from selected rows in a fixed width file using a shell?
Input is like
abcd1234
xyzd1234
abcd
a1b2c3d4
abcd1234
xyzd1234
xx
abcd1234
Expected output -
abcd1234xyzd1234
abcda1b2c3d4abcd1234xyzd1234
xxabcd1234
... (3 Replies)
I have a file ABC.DAT with 2 columns avaialble
Data format :
XYZ!$#$!120
XXZ!$#$!1000
YYZ!$#$!104
While running the following code :
FILE_COUNTER=1;
RECORD_CN_FILE_COUNT=$((`wc -l ABC.DAT| cut -f1 -d' '`));
while
do
FILE_NAME=`cat ABC.DAT.DAT| head -$FILE_COUNTER |tail -1 | awk -F... (1 Reply)
Input eg:
Ouput Expected.
The #rd line had the unexpted new line, which need to be replaced with space.
I was planing to go with checking the length of each line using awk and if the length is less than the defeined limit, (12 in above case) will replace the newline with space.
... (5 Replies)
Discussion started by: deepakwins
5 Replies
LEARN ABOUT LINUX
deb-split
deb-split(5) Debian deb-split(5)NAME
deb-split - Debian multi-part binary package format
SYNOPSIS
filename.deb
DESCRIPTION
The multi-part .deb format is used to split big packages into smaller pieces to ease transport in small media.
FORMAT
The file is an ar archive with a magic value of !<arch>. The file names might contain a trailing slash (since dpkg 1.15.6).
The first member is named debian-split and contains a series of lines, separated by newlines. Currently seven lines are present. The first
is the format version number, 2.1 at the time this manual page was written. The second is the package name. The third is the package ver-
sion. The fourth is the md5sum of the package. The fifth is the total size of the package. The sixth is the maximum part size. The seventh
is the current part number, followed by a slash and the total amount of parts (as in '1/10').
Programs which read multi-part archives should be prepared for additional lines to be present, and should ignore these if this is the case.
If the version number has changed, an incompatible change has been made and the program should stop. If it has not, then the program should
be able to safely continue, unless it encounters an unexpected member in the archive (except at the end), as described below.
The second, last required member is named data.N, where N denotes the part number. It contains the raw part data.
These members must occur in this exact order. Current implementations should ignore any additional members after data.N. Further members
may be defined in the future, and (if possible) will be placed after these two.
SEE ALSO deb(5), dpkg-split(1).
Debian Project 2010-01-28 deb-split(5)