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Full Discussion: An other awk problem
Top Forums UNIX for Advanced & Expert Users An other awk problem Post 10927 by Jimbo on Sunday 25th of November 2001 10:00:38 AM
Old 11-25-2001
Nice code, Perderabo.

Here is an awk solution:
Code:
#!/bin/sh

year=$1
month=$2
week=$3
day=$4

export month week day

cal $month $year | cat -n |
awk -v m=$month -v w=$week -v d=$day \
   'BEGIN {split("Jan Feb ... Nov Dec",mo)
           split("Sun Mon Tue Wed Thu Fri Sat",dow)}
    NF>1&&$1==w+2 {
       if (d>=NF)
           print "non-existant day of week"
        else
           print dow[d+8-NF], mo[m], $(d+1)}'

You need to expand the month array where I have "...". I am assuming that when week 1 starts on Thursday, then Thursday would be day 1.

Output format is: Tue Nov 20

added code tags for readability --oombera
Last edited by oombera; 02-20-2004 at 12:41 PM..
Jimbo
 

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LEARN ABOUT PHP

intlcalendar.getminimaldaysinfirstweek

INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)				 1				 INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)

IntlCalendar::getMinimalDaysInFirstWeek - Get minimal number of days the first week in a year or month can have

	Object oriented style

SYNOPSIS

       public int IntlCalendar::getMinimalDaysInFirstWeek (void  )

DESCRIPTION

	Procedural style
       int intlcal_get_minimal_days_in_first_week (IntlCalendar  $cal)

	Returns  the  smallest number of days the first week of a year or month must have in the new year or month. For instance, in the Gregorian
       calendar, if this value is 1, then the first week of the year will necessarily include January 1st, while if this value is 7, then the week
       with  January  1st  will  be the first week of the year only if the day of the week for January 1st matches the day of the week returned by
       IntlCalendar.getFirstDayOfWeek(3); otherwise it will be the previous years last week.

PARAMETERS

	      o $cal
		- The IntlCalendar resource.

RETURN VALUES

	An int representing a number of days or FALSE on failure.

EXAMPLES

       Example #1

	      IntlCalendar.getMinimalDaysInFirstWeek(3)

	      <?php
	      ini_set('date.timezone', 'UTC');
	      ini_set('intl.default_locale', 'en_US');

	      $cal = new IntlGregorianCalendar(2013, 0 /* January */, 2);
	      var_dump(IntlDateFormatter::formatObject($cal, 'cccc')); // Wednesday

	      var_dump($cal->getMinimalDaysInFirstWeek(), // 1
	      $cal->getFirstDayofWeek()); // 1 (Sunday)

	      // Week 1 of 2013
	      var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));

	      $cal->setMinimalDaysInFirstWeek(4);
	      // Still Week 1 of 2013 (1st week has 5 days in the new year)
	      var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));

	      $cal->setMinimalDaysInFirstWeek(6);
	      // Week 53 of 2012
	      var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));

	      The above example will output:

	      string(9) "Wednesday"
	      int(1)
	      int(1)
	      string(14) "Week 1 of 2013"
	      string(14) "Week 1 of 2013"
	      string(15) "Week 53 of 2012"

PHP Documentation Group 										 INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)
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