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Top Forums Shell Programming and Scripting Schedule and Run By weekly shell script in cronjob Post 302785625 by krupasindhu18 on Tuesday 26th of March 2013 05:08:55 AM
Old 03-26-2013
Hi,
Actually my Requirement is like this :-
I have shell script in kern shell ,have to run alternate week per month
example-today's date is 27 Mar 2013 and my script will run today then for the next time when it will run it should check 1st what was the last run date(27 Mar 2013) if it is matched 15days from current date then run else sent a mail with waning mgs.

i have a AWK command it is checking only within a month
Code:
Code:
date +%Y:%m:%d|awk -vFS=":" -vOFS=":" '{$3=$3-3;print}'

suppose i am checking 20days from current date it is give some negative value(-8)
ex-2013:03:-8

I hope you will understand my problem.
Advance thanks for giving me solution.

Thank you All.

Regards,
Krupa

---------- Post updated at 04:08 AM ---------- Previous update was at 04:05 AM ----------

Quote:
Originally Posted by Jotne
Every week
Code:
0 0 * * 0 byweeklyreport.sh

CronBuddy - a crontab sandbox

i don't think you are reading properly my thread
please read carefully and replu me back

Last edited by Franklin52; 03-26-2013 at 06:39 AM.. Reason: Code tags
 

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INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)				 1				 INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)

IntlCalendar::getMinimalDaysInFirstWeek - Get minimal number of days the first week in a year or month can have

	Object oriented style

SYNOPSIS
public int IntlCalendar::getMinimalDaysInFirstWeek (void ) DESCRIPTION
Procedural style int intlcal_get_minimal_days_in_first_week (IntlCalendar $cal) Returns the smallest number of days the first week of a year or month must have in the new year or month. For instance, in the Gregorian calendar, if this value is 1, then the first week of the year will necessarily include January 1st, while if this value is 7, then the week with January 1st will be the first week of the year only if the day of the week for January 1st matches the day of the week returned by IntlCalendar.getFirstDayOfWeek(3); otherwise it will be the previous years last week. PARAMETERS
o $cal - The IntlCalendar resource. RETURN VALUES
An int representing a number of days or FALSE on failure. EXAMPLES
Example #1 IntlCalendar.getMinimalDaysInFirstWeek(3) <?php ini_set('date.timezone', 'UTC'); ini_set('intl.default_locale', 'en_US'); $cal = new IntlGregorianCalendar(2013, 0 /* January */, 2); var_dump(IntlDateFormatter::formatObject($cal, 'cccc')); // Wednesday var_dump($cal->getMinimalDaysInFirstWeek(), // 1 $cal->getFirstDayofWeek()); // 1 (Sunday) // Week 1 of 2013 var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y")); $cal->setMinimalDaysInFirstWeek(4); // Still Week 1 of 2013 (1st week has 5 days in the new year) var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y")); $cal->setMinimalDaysInFirstWeek(6); // Week 53 of 2012 var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y")); The above example will output: string(9) "Wednesday" int(1) int(1) string(14) "Week 1 of 2013" string(14) "Week 1 of 2013" string(15) "Week 53 of 2012" PHP Documentation Group INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)
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