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Top Forums UNIX for Dummies Questions & Answers Finding difference in 1st field for rows of data Post 302767843 by co21ss on Thursday 7th of February 2013 02:57:51 PM
Old 02-07-2013
Quote:
Originally Posted by RudiC
Not clear. The file seems to be comma AND multiple space delimited. AND, first four lines (and next four ... etc.) seem to contain identical values. It's easy to set a flag on a field changing, but to what avail? Where does $1 == "1" into play? I don't see a connection between your input sample and the desired output you post. Pls be more specific, post more detailed input / output samples.
And, btw, don't use $f in your awk script. That's a shell'ism; use f to reference the variable itself. In awk, $f would address the f'th field of the input line...
Sorry for not being clear. The code is not space separated, but just shown as such to clarify the input. Here is a better example:

Typical input -
Code:
"20","file1","xxxx"
"20","file1","xxxx"
"20","file1","xxxx"
"20","file1","xxxx"
"20","file2","yyyy"
"20","file2","yyyy"
"20","file2","yyyy"
"20","file2","yyyy"
"20","file3","zzzz"
"20","file3","zzzz"
"20","file3","zzzz"
"20","file3","zzzz"

Non-typical input -
Code:
"1","file1","xxxx"
"20","file1","xxxx"
"20","file1","xxxx"
"20","file1","xxxx"
"20","file2","yyyy"
"20","file2","yyyy"
"5","file2","yyyy"
"20","file2","yyyy"
"20","file3","zzzz"
"20","file3","zzzz"
"20","file3","zzzz"
"20","file3","zzzz"

In the non-typical input case, I would like to create an output, such as "FAIL", to use in a later routine if the 1st field is different from the rest for any of the individual files.

The 1st field will not always be known, but however is a value input from another file entirely. The goal here is run a script to automate having to visually look through the file for differences in the 1st field for any "file1" or "file2" lines of the file.

Last edited by co21ss; 02-07-2013 at 05:08 PM.. Reason: clarification
 

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INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)				 1				 INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)

IntlCalendar::getMinimalDaysInFirstWeek - Get minimal number of days the first week in a year or month can have

	Object oriented style

SYNOPSIS
public int IntlCalendar::getMinimalDaysInFirstWeek (void ) DESCRIPTION
Procedural style int intlcal_get_minimal_days_in_first_week (IntlCalendar $cal) Returns the smallest number of days the first week of a year or month must have in the new year or month. For instance, in the Gregorian calendar, if this value is 1, then the first week of the year will necessarily include January 1st, while if this value is 7, then the week with January 1st will be the first week of the year only if the day of the week for January 1st matches the day of the week returned by IntlCalendar.getFirstDayOfWeek(3); otherwise it will be the previous years last week. PARAMETERS
o $cal - The IntlCalendar resource. RETURN VALUES
An int representing a number of days or FALSE on failure. EXAMPLES
Example #1 IntlCalendar.getMinimalDaysInFirstWeek(3) <?php ini_set('date.timezone', 'UTC'); ini_set('intl.default_locale', 'en_US'); $cal = new IntlGregorianCalendar(2013, 0 /* January */, 2); var_dump(IntlDateFormatter::formatObject($cal, 'cccc')); // Wednesday var_dump($cal->getMinimalDaysInFirstWeek(), // 1 $cal->getFirstDayofWeek()); // 1 (Sunday) // Week 1 of 2013 var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y")); $cal->setMinimalDaysInFirstWeek(4); // Still Week 1 of 2013 (1st week has 5 days in the new year) var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y")); $cal->setMinimalDaysInFirstWeek(6); // Week 53 of 2012 var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y")); The above example will output: string(9) "Wednesday" int(1) int(1) string(14) "Week 1 of 2013" string(14) "Week 1 of 2013" string(15) "Week 53 of 2012" PHP Documentation Group INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)
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