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unix script that will pick up first 10 file

 
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# 1  
Old 11-05-2008
unix script that will pick up first 10 file
Suppose I have a unix file which contain a lost of 60 files like

filename1
filename2
...
..
...
filename60

I want to write a unix script that will pick up first 10 files in first run
10-20 files in 2 run
20-30 files in 3 run
30-40 files in 4 run
40-50 files in 5 run
50-60 files in 6 run Image Image
# 2  
Old 11-05-2008
1-10 , 11-20 is ten files. 10-20 is eleven.
Code:
# parameter $1 is the starting number, eg 31 or 21 or 1
# usage script.sh 31
awk -v start="$1" ' {
              if( FNR >= start and FNR <= start + 10) {print $0}
              continue
            }'   inputfilename

 
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